Ask question

Ask question

All categories

ValentinkaMS [17]

3 years ago

9

Please help with this questions!

1 answer:

amid [387]3 years ago

7 0

He began at 3:44pm
3:44 + 3:45 = 7:29

You might be interested in

What is the system of inequalities associated with the following graph?

Ludmilka [50]

Answer:

1,1

Step-by-step explanation:

4 0

3 years ago

Q-U-E-S-T-I-O-N: Whats 1000000000000000000000000 multiplyed by 20000000<br> Its a weird word :/

Oksana_A [137]

Answer:

2e+31

Step-by-step explanation:

8 0

3 years ago

There is 120 ft of fencing available for a project. What would be the dimensions for the garden if the builders attached one sid

Pavlova-9 [17]

30 x 60

Step-by-step explanation:

the length of the perimeter would be 180, subtract 60ft for the fencing replaced by the wall and you meet the maximum 120ft

30X60 gives you the largest area with 1800ft^2

5 0

3 years ago

The highway department is testing two types of reflecting paint for concrete bridge end pillars. The two kinds of paint are alik

tankabanditka [31]

Answer:

a. difference of means

Step-by-step explanation:

Given that :

Mean , x = 9.4

Standard deviation, $s.d_1$ = 2.5

Number, $n_1$ = 12

Mean, y = 6.5

standard deviation, $s.d_2$ = 2.4

Number, $n_2$ = 12

The null hypothesis is : $H_0: \mu_1=\mu_2$

The alternate hypothesis is : $H_1: \mu_1>\mu_2$

Level of significance, $\alpha$ = 0.1

From the $\text{standard normal table, right tailed,}$ $t_{1/2}$ = 1.363

Since out test is right tailed.

Reject $H_0$ , if $T_0>1.363$

We use the test statics,

$t_0=\frac{(x-y)}{\sqrt{\frac{s.d_1}{n_1}+\frac{s.d_2}{n_2}}}$

$t_0=\frac{(9.4-6.5)}{\sqrt{\frac{6.25}{12}+\frac{5.76}{12}}}$

$t_0=2.899$

$|t_0|=2.899$

$\text{Critical value}$

The value of $|t_{1/2}|$ with minimum $\left(n_1-1,n_2-1)$ that is 11 df is 1.363

We go $|t_0|=2.899$ and $|t_{1/2}|$ = 1.363

Decision making:

Since the value of $|t_0|>|t_{1/2}|$$ and we reject the $H_0$

The p-value : right tail $H_a:(p>2.8988)$

= 0.00724

Therefore the value of $p_{0.1} > 0.00724$ , and so we reject the $H_0$

Thus we are testing 'the difference of means" in this problem.

7 0

3 years ago

In February, Alec had 1,571 visitors to his website. In March, he had 1,380 visitors to his website. What is the percentage decr

Yakvenalex [24]

A. 12.2%

Steps:
1) 1380-1571= -191
2) -191/1571= -0.12
3) -0.12(100) = 12.15 = 12.2%

3 0

4 years ago