8(8n +4)= -480<br><br> Help plz..And No links!! I repeat No links!!

Factorize a⁴-6a²-7-8x-x²

ANEK [815]

Answer:a⁴-7-x²-6a²-8x

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2 years ago

NEED HELP PLEASE FAST!

Aleks [24]

For one it would be c and d
Two x is greater than seven
three would be x is greater than or equal to 6
Four would be subtract eight from both sides you get 24 and then divide by negative four which gets you negative six but then you have to turn the sign around. Number set would be anything above negative six,so like negative five, 52, and one
Five would be subtract 3 from both sides giving you 5 on the right side and then multiply by six on both sides giving you thirty on the right side, resulting in x is greater than or equal to thirty. Three numbers that would work would be thirty, fifty nine, and thirty five.

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3 years ago

Tim claims that a coin is coming up tails less than half of the time. In 110 tosses, the coin comes up tails 47 times. Using P-v

lilavasa [31]

Answer:

$z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531$

$p_v =P(z$

If we compare the p value obtained and using the significance level given $\alpha=0.1$ we have that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=47 represent the number of tails obtained

$\hat p=\frac{47}{110}=0.427$ estimated proportion of tails

$p_o=0.5$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of tails is lower than 0.5:

Null hypothesis: $p\geq 0.5$

Alternative hypothesis: $p < 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

If we compare the p value obtained and using the significance level given $\alpha=0.1$ we have that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.

6 0

3 years ago

Simplify the following expression.<br><br> 0.82 / 0.2

AlekseyPX

Answer:

0.41

Step-by-step explanation:

0.82 = 0.2 x 0.41

0.82 / 0.2

= ( 0.2 x 0.41 ) / 0.2

= 0.41

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