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Anastaziya [24]
2 years ago
14

Please help! i need this one if i want to pass

Mathematics
1 answer:
Olin [163]2 years ago
4 0

Answer:

option b is right..........

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A survey was done where males and females were asked if they would prefer to eat chicken or steak. The results of the survey are
alexgriva [62]

Answer:

Step-by-step explanation:

Number of tickets for international flights = 36

Total number of tickets = 95

The probability that a randomly selected airline ticket is for an international flight = 36 / 95 = 0.3789

The probability that a randomly selected airline ticket is for an international flight as a percent rounded to the nearest tenth of a percent = 0.3789 x 100 = 37.9%

% of males surveyed = 0.236 + 0.218 = 0.454 = 45.4%

% of males surveyed who prefer chicken = 0.236 out of 0.454 = 0.236 / 0.454 = 0.5198 = 51.58% = 52.0%

<em>hope this helps~</em>

6 0
3 years ago
Read 2 more answers
Which function is equivalent to h(x)=10x2+9x-1?
jolli1 [7]

Answer:

i think the answer is c

Step-by-step explanation:

4 0
3 years ago
Find the volume of the cone.
Andrew [12]

Answer:

V= 628.32

Step-by-step explanation:

4 0
3 years ago
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa
gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4  | red dice) = \dfrac{1}{6}

P (4 | green dice) = \dfrac{3}{6} =\dfrac{1}{2}

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = \dfrac{1}{2}

The probability of two 1's and two 4's in the first dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^4

= \dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4

= 6 \times ( \dfrac{1}{6})^4

= (\dfrac{1}{6})^3

= \dfrac{1}{216}

The probability of two 1's and two 4's in the second  dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^2  \times  \begin {pmatrix} \dfrac{3}{6}  \end {pmatrix}  ^2

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= 6 \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= ( \dfrac{1}{6}) \times  ( \dfrac{3}{6})^2

= \dfrac{9}{216}

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = \dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}

The probability of two 1's and two 4's in both die = \dfrac{1}{432}  + \dfrac{1}{48}

The probability of two 1's and two 4's in both die = \dfrac{5}{216}

By applying  Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's )  = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's )  = \dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}

P(second die (green) | two 1's and two 4's )  = \dfrac{0.5 \times 0.04166666667}{0.02314814815}

P(second die (green) | two 1's and two 4's )  = 0.9

Thus; the probability the die chosen was green is 0.9

8 0
3 years ago
Which of the following question is not considered a statistical question?
vekshin1

Answer:

B. How many total customers were at the story today?

Step-by-step explanation:

Option 'B' is not a statistical question because there is not more than one answer.

There is only one answer to this question.

Option 'A,' 'C,' and 'D' are statistical questions because there is more than one answer.

<em>What amounts did each person at the store spend on their purchase?</em>

This question has more than one answer.

<em>How long did each customer spend shopping at the store?</em>

<em>What are the heights of each customer who entered the store?</em>

These questions have more than one answer as well.

Statistical questions are questions that have more than one answer. This means you can collect data.

I, therefore, believe that option 'B' is not a statistical question.

7 0
2 years ago
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