(1) y= - x² - 4x + 9 and (2) y + 5x = - 7. Isolate y in (2); y= - 5x - 7 (3)
Since (1) and (3) have the same value or the same y, then we can write:
(1)=(3)
- x² - 4x + 9 = - 5x - 7
-x² - 4x + 9 + 5x +7 = 0
-x² + x + 16 = 0 OR x² - x - 16 = 0
Solve this quadratic equation:
x' = [-b+√(b²-4ac)]/(2a) and x" = [-b-√(b²-4ac)]/(2a)
x' = [+1+√(-1)² - 4(1)(-16)]/2 → x' = [1+√(1+64)]/2 → x' = [1+√65)]/2
x" = [+1-√(-1)² - 4(1)(-16)]/2 → x' = [1-√(1+64)]/2 → x' = [1-√65)]/2
x' = [1+√65)]/2 = + 4.5311
x" =[1-√65)]/2 = - 3.5311
1:2...added = 3
1/3(18) = 18/3 = 6 (yellow chalk)
2/3(18) = 36/3 = 12 (not yellow)
so 6 pieces are yellow and 12 pieces are not
Answer:
Sin X=Cos Y
Step-by-step explanation:
Objective: Understand trigonometric relations such that
Cosine and Sine are similar to complementary angles that if X+Y are complementary angles,
Cos X= Sin Y and Cos Y= Sin X
Answer:
It's a negative 4 and the variable n and can be used for anything or any equation.
