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Blizzard [7]
3 years ago
13

Manuel took 2 2/5

Mathematics
1 answer:
yan [13]3 years ago
3 0
1 whole hour... 2 2/5 x 3 - 1 1/3 x 5=2 6/15 - 1 5/15. (Reduced) 1 1/1
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A toy factory sold 120,587 toys in 25 days. If each toy was sold for $58, about how much money did the factory earn in 25 days?
Rina8888 [55]
<h3>Answer: $7,018,000</h3>

This value is a little over 7 million dollars

======================================================

Explanation:

120,587 rounds to 121,000 when rounding to the nearest thousand.

The instructions don't mention rounding 58, so we'll leave it as that

Multiply the values to get

58*121,000 = 7,018,000

which is the estimate of how much money was earned.

-----------

The actual amount of money earned is

58*120,587 = 6,994,046

which isn't too far off of our estimate.

-----------

Note: the value of 25 days is never used. You could have any other number of days you want, and the answer is still the same. This value is probably either filler or some kind of distraction.

6 0
3 years ago
HELPPPP PLZZZ!!!! I need this done soon
irakobra [83]

Answer:

y=-7/10x+107........

4 0
3 years ago
4. A plane was flying at an altitude of 55,000 feet when it began the descent toward the airport. The airplan
marin [14]

Answer:

Step-by-step explanation:

A Descent rate,

B 10725ft,

C 25min

8 0
2 years ago
Read 2 more answers
For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

7 0
3 years ago
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Solve the inequality 0&lt;5x-2&lt;8
zloy xaker [14]

Answer:

×= 2 this is what I got as a result to my equations

8 0
3 years ago
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