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Ksju [112]
3 years ago
14

A choir teacher is dividing 15 sopranos and 36 altos into the singing groups. He wants each group to have the same combination o

f sopranos and altos, with no singers left over. What is the greatest number of groups?​
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

3 groups of 5 sopranos and 12 altos

Step-by-step explanation:

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PLSS ANSWER MY QUESTION
Taya2010 [7]

Answer:

1) Area of frame: 140cm^2 ; Area of picture: 40cm^2 ; Total Area: 180cm^2.      

2) Area 1 =  48cm^2 ; Area 2 = 12cm^2 ; total area = 60cm^2 [first answer line : 60cm^2]

Step-by-step explanation:

1. So to answer this question, you have to find the inner photo area first (which you will then subtract from the overall rectangle area to get the photo frame area).

To find area, you multiply length x width. For this question, there are not enough measurements given to initially multiply length and width. So, assuming that the photo is centered on the frame and the frame width is consistent along all sides, you find the difference between the overall length (12) and the picture length (5).

12 - 5 = 7

The leftover area (outside of the picture) is 7 cm (half of seven on both sides), so one side can be assumed to be : 3.5 cm

this means that 15 cm - 3.5 cm of both sides lengths (difference between the two lengths given) is the height of the photo, 15 - 3.5(2) = 8

So, the dimensions/measurements of the photo are 5 cm by 8 cm.

This means that the inner photo area is 40 (5 x 8) cm

The area of the frame will be the area of the total rectangle [12 x 15] - the inner photo area [40].  [ (12)(15) - 40 ]

[180 - 40] = 140 cm

(area is measured in squared units, so the area of the frame should be written as 140cm^{2} ; and the area of the photo should be written as 40cm^{2})

The total area is the entire area of the rectangle: (12)(15) = 180. (This should be written as 180cm^2)

--------------------------------------

2) Finding the area of a shape that isn't a simple rectangle is easier if you separate the shape into smaller rectangles. I will separate the two rectangles into 4 x 12 and 2 x 6 [6 cm would be the remaining side length if you remove the length of 4].

{you can separate the shape in multiple ways, so my answer is only one answer to this problem out of other splits.}

as mentioned, the area is length x width.

4 x 12 = 48.

2 x 6 = 12. Once again, you should write area in squared units.

(the area 1 should be written as 48cm^{2} ; the area 2 should be written as 12cm^2)

you can combine the separated areas (add them) to find the total area. 48 + 12 = 60.

(the total area should be written in squared units also, so the total area should be written as: 60cm^2)

The area of the figure is 60cm^2

8 0
2 years ago
Solve the triangle that has a=4.6, B=19°, A=92° (picture provided)
kolezko [41]

Answer:

Option b

Step-by-step explanation:

To solve this problem use the law of the sines.

We have 2 angles of the triangle and one of the sides.

a = 4.6\\B = 19\°\\A = 92\°\\C = 180 -A - B\\C = 180 - 92 - 19\\C = 69\°

The law of the sines is:

\frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}

Then:

\frac{sin(92)}{4.6} = \frac{sin(19)}{b}\\\\b = \frac{sin(19)}{\frac{sin(92)}{4.6}}\\\\b = 1.5

\frac{sin(B)}{b} = \frac{sin(C)}{c}\\\\\frac{sin(19)}{1.5} = \frac{sin(69)}{c}\\\\c = \frac{sin(69)}{\frac{sin(19)}{1.5}}\\\\c = 4.30

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kolbaska11 [484]

Answer:

<em>(IQR) interquartile range: 12 - 9 = 3</em>

Step-by-step explanation:

Median: 10

Lower quartile: 9

Upper quartile: 12

Interquartile Range: 12 - 9 = 3

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4 years ago
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