All categories

3 years ago

Simplify the following expression.

Mathematics

1 answer:

Anestetic [448]3 years ago

6 0

Answer:

Step-by-step explanation:

4(20 + 12) = (5-3).

4(20+12) = 2. Divide both sides by 2.

2(32) = 64

You might be interested in

Prove that: (b²-c²/a)CosA+(c²-a²/b)CosB+(a²-b²/c)CosC = 0

IRISSAK [1]

Prove that:

$\:\:\sf\:\:\left(\dfrac{b^2-c^2}{a}\right)\cos A+\left(\dfrac{c^2-a^2}{b}\right)\cos B +\left(\dfrac{a^2-b^2}{c}\right)\cos C=0$

Proof: 

We know that, by Law of Cosines,

$\sf \cos A=\dfrac{b^2+c^2-a^2}{2bc}$
$\sf \cos B=\dfrac{c^2+a^2-b^2}{2ca}$
$\sf \cos C=\dfrac{a^2+b^2-c^2}{2ab}$

Taking LHS

$\left(\dfrac{b^2-c^2}{a}\right)\cos A+\left(\dfrac{c^2-a^2}{b}\right)\cos B +\left(\dfrac{a^2-b^2}{c}\right)\cos C$

Substituting the value of cos A, cos B and cos C,

$\longmapsto\left(\dfrac{b^2-c^2}{a}\right)\left(\dfrac{b^2+c^2-a^2}{2bc}\right)+\left(\dfrac{c^2-a^2}{b}\right)\left(\dfrac{c^2+a^2-b^2}{2ca}\right)+\left(\dfrac{a^2-b^2}{c}\right)\left(\dfrac{a^2+b^2-c^2}{2ab}\right)$

$\longmapsto\left(\dfrac{(b^2-c^2)(b^2+c^2-a^2)}{2abc}\right)+\left(\dfrac{(c^2-a^2)(c^2+a^2-b^2)}{2abc}\right)+\left(\dfrac{(a^2-b^2)(a^2+b^2-c^2)}{2abc}\right)$

$\longmapsto\left(\dfrac{(b^2-c^2)(b^2+c^2)-(b^2-c^2)(a^2)}{2abc}\right)+\left(\dfrac{(c^2-a^2)(c^2+a^2)-(c^2-a^2)(b^2)}{2abc}\right)+\left(\dfrac{(a^2-b^2)(a^2+b^2)-(a^2-b^2)(c^2)}{2abc}\right)$

$\longmapsto\left(\dfrac{(b^4-c^4)-(a^2b^2-a^2c^2)}{2abc}\right)+\left(\dfrac{(c^4-a^4)-(b^2c^2-a^2b^2)}{2abc}\right)+\left(\dfrac{(a^4-b^4)-(a^2c^2-b^2c^2)}{2abc}\right)$

$\longmapsto\dfrac{b^4-c^4-a^2b^2+a^2c^2}{2abc}+\dfrac{c^4-a^4-b^2c^2+a^2b^2}{2abc}+\dfrac{a^4-b^4-a^2c^2+b^2c^2}{2abc}$

On combining the fractions,

$\longmapsto\dfrac{(b^4-c^4-a^2b^2+a^2c^2)+(c^4-a^4-b^2c^2+a^2b^2)+(a^4-b^4-a^2c^2+b^2c^2)}{2abc}$

$\longmapsto\dfrac{b^4-c^4-a^2b^2+a^2c^2+c^4-a^4-b^2c^2+a^2b^2+a^4-b^4-a^2c^2+b^2c^2}{2abc}$

Regrouping the terms,

$\longmapsto\dfrac{(a^4-a^4)+(b^4-b^4)+(c^4-c^4)+(a^2b^2-a^2b^2)+(b^2c^2-b^2c^2)+(a^2c^2-a^2c^2)}{2abc}$

$\longmapsto\dfrac{(0)+(0)+(0)+(0)+(0)+(0)}{2abc}$

$\longmapsto\dfrac{0}{2abc}$

$\longmapsto\bf 0=RHS$

LHS = RHS proved.

7 0

2 years ago

Guys! Help please! What are the characteristics of squares, rhombi, kites, and trapezoids?

Kay [80]

they are all quadrilateral s

hope this helps ;)

3 0

2 years ago

Read 2 more answers

⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ a(1)=−13 a(n)=a(n−1)+4 Find the 2nd2^{\text{nd}} 2 nd 2, start superscript, start text, n, d, end text, end su

Fofino [41]

Answer:

a(2) = -9

Step-by-step explanation:

It looks like you want the 2nd term in the arithmetic sequence defined by the recursive formula ...

a(1) = -13
a(n) = a(n -1) +4

Using the formula with n=2, we have ...

a(2) = a(1) +4

a(2) = -13 +4 . . . . substitute the value of a(1)

a(2) = -9

8 0

3 years ago

A quadrilateral PQRS is translated to the left by 4 units to obtain another quadrilateral P᾿Q᾿R᾿S᾿

IrinaVladis [17]

Answer:

the length of PQ is equal to the length of P'Q'

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, rotation, translation and dilation.

Translation is the movement of a point either up, down, right or left. Translation is a type of rigid transformation. Rigid transformation is a transformation in which both the image and pre-image have the same shape and size. types of rigid transformation are rotation, reflection and translation.

Quadrilateral PQRS is translated to the left by 4 units to obtain another quadrilateral P᾿Q᾿R᾿S᾿. Since translation is a rigid transformation, the shape and size of PQRS is the same as that of P'Q'R'S. Hence the length of PQ is equal to the length of P'Q'.

8 0

3 years ago

A right rectangular prism's edge lengths are 4.1 inches, 4 inches, and 3 inches. How many unit cubes with edge

dangina [55]

Answer:

D: 1458 Unit Cubes

6 0

2 years ago