All categories

3 years ago

If r(x) = 2 – x2 and w(x) = x – 2, what is the range of w(r(x))

Mathematics

2 answers:

shepuryov [24]3 years ago

8 0

(-infinity,0] is the answer.

Paladinen [302]3 years ago

5 0

Range is the outputs possible
w(r(x))=(2-x^2)-2
w(r(x))=2-x^2-2
w(r(x))=-x^2

therefor the range is from 0 to -∞

You might be interested in

Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

Answer Check

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$

The equation is true for both roots.

Answer

$\large \boxed {3 {x}^{2} - 14x - 5 = 0}$

8 0

2 years ago

Can someone help me with my algebra class?

Lilit [14]

Im stuck on algebra too

3 0

3 years ago

Which phrase describes the pattern? 1, 3, 11, 123,...

Monica [59]

D) square the number and add 2

7 0

3 years ago

Read 2 more answers

Restate this: Historians know about the past before there were written records by studying artifacts

Natali [406]

Answer:

There were written records by studying aircrafts before historians know about the past.

Step-by-step explanation:

8 0

2 years ago

The Jones family has saved a maximum of $750 for their family vacation to the beach. While planning the trip, they determine th

Lemur [1.5K]

Answer:

Value of h greater than 5.4 will make inequality false.

Step-by-step explanation:

This question is incomplete; here is the complete question.

The Jones family has saved a maximum of $750 for their family vacation to the beach. While planning the trip, they determine that the hotel will average $125 a night and tickets for scuba diving are $75. The inequality can be used to determine the number of nights the Jones family could spend at the hotel 750 ≥ 75 + 125h. What value of h does NOT make the inequality true?

From the given question,

Per night expense (expected) = $125

If Jones family stays in the hotel for 'h' days then total expenditure on stay = $125h

Charges for scuba diving = $75

Total charges for stay and scuba diving = $(125h + 75)

Since Jones family has saved $750 for the vacation trip so inequality representing the expenses will be,

125h + 75 ≤ 750

125h ≤ 675

h ≤ $\frac{675}{125}$

h ≤ 5.4

That means number of days for stay should be less than equal to 5.4

and any value of h greater than 5.4 will make the inequality false.

3 0

2 years ago