2.40 divided by 6 is 0.40 so 0.40 times 10 is 4.00
Answer:
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The present age of Jane is 45 years old and present age of her sister is 9 years old
<em><u>Solution:</u></em>
Let the present age of Jane be "x"
Let the present age of her sister be "y"
<em><u>Jane is 5 times older than her sister</u></em>
present age of Jane = 5(present age of her sister)
x = 5y ---------- eqn 1
<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>
Age of sister after 3 years = 3 + y
Age of jane after 3 years = 3 + x
Age of sister after 3 years = 1/4(age of jane after 3 years)

Substitute eqn 1 in above equation

Substitute y = 9 in eqn 1
x = 5(9)
x = 45
Thus present age of Jane is 45 years old and present age of her sister is 9 years old
Using the identity cos(2x) = 2 cos^2x - 1
18 + 9(2 cos^2 x - 1) = 27 cos x
18cos^2 x - 27 cos x + 9 = 0
2 cos^ x - 3 cos x + 1 = 0
(2 cos x - 1 )(cos x - 1 ) = 0
cos x = 1/2 , 1
x = pi/3, 5pi/3, 0, 2pi answer
-32+<u>50</u> =2(x^2+10x+25)
18=2(x+5)^2
9= (x+5)^2
+-<u /> <u>3</u> = x+5
x= -2 or x= <u>-8</u>