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Hi there!
The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Answer:
I think its A
Step-by-step explanation:
I factored the polynomial and its factors turned out to be (x-1)(x^2-2x-4), which eliminated the possibilities of 2 and 3. Then i replaced the (-1) in the place of the x and it turned out to be equal to 2, making the first statement true.
We have 1 m = 100cm
⇒ 72 m = 7200 cm
⇒ 7200 / 1.5= 4800 cm = 48 m
Answer: A'(-3, 7), B'(3, 6), C'(-7, -2)
Step-by-step explanation:
Reflecting over y = x maps (x,y) onto (y,x).
