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3 years ago

ANY MATH EXPERTS PLS HELP RN I GOT 30 MIN LEFT I PUT 100 POINTS

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

8 0

Answer:

y = -1/4x-6

Step-by-step explanation:

y=mx+b

Use slope equation m = (y1 - y2) / (x1 - x2)

b is the y intercept : -6

Alika [10]3 years ago

8 0

Answer:

y=-1/4x+(-6)

Step-by-step explanation:

Slope intercept form is y=mx+b. To find the slope, pick 2 points the line crosses through and divide the rise by the run. You can see the y-intercept on the graph. Therefore the equation should be y=-1/4x+(-6).

HTH :)

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Consider the line 5x-8y=8 what is the slope of a line perpendicular to this line what is the slope of a line parallel to this li

Sophie [7]

$\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2,\ \text{then}\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\\text{Convert the equation to the slope-intercept form}\ y=mx+b.\\\\5x-8y=8\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-8y=-5x+8\qquad\text{divide both sides by (-8)}\\\\y=\dfrac{5}{8}x-1\to m_1=\dfrac{5}{8}\\\\perpendicular:\ m_2=-\dfrac{1}{\frac{5}{8}}=-\dfrac{8}{5}\\\\parallel:\ m_2=\dfrac{5}{8}$

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3 years ago

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

The 1.8 million cars use $1.85 \times 10^{10}$ liters each year

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

Hence, the number of liters used is $1.85 \times 10^{10}$

Read more about distance and rates at:

brainly.com/question/24659604

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3 years ago

3. Which expression is equivalent to log532?

saul85 [17]

Answer: The Nth power xN of a number x was originally defined as x multiplied by itself, until there is a total of N identical factors. By means of various generalizations, the definition can be extended for any value of N that is any real number.

(2) The logarithm (to base 10) of any number x is defined as the power N such that

x = 10N

(3) Properties of logarithms:

(a) The logarithm of a product P.Q is the sum of the logarithms of the factors

log (PQ) = log P + log Q

(b) The logarithm of a quotient P / Q is the difference of the logarithms of the factors

log (P / Q) = log P – log Q

log[PQ] = Q.logP

Step-by-step explanation:

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3 years ago

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dalvyx [7]

Answer:

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_______. ____

x 5

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2 years ago

Read 2 more answers

Which sampling would be appropriate to survey 120,000 people?

kipiarov [429]

Answer: Id say b

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3 years ago