the first one that is x-99....... goes to the second answer box
the second that is x-51......... goes to the first answer box
the third that is 150+x......... goes to the fourth answer box
the fourth that is 69-x......... goes to the third answer box
Answer
The vertex is at point (-3, -1)
The axis of symmetry is x = -3
Explanation
We are asked to find the vertex and axis of symmetry of the equation given.
f(x) = x² + 6x + 8
The vertex of a quadratic equation is the point where the graph of the quadratic equation changes from sloping negatively to sloping positively and vice-versa.
The axis of symmetry represents the straight line that divides the graph of the quadratic equation into two mirror parts that are similar to and are mirror images of each other. This axis of symmetry usually passes through the vertex.
To find the vertex, it is usually at the turning point where the first derivative of the quadratic equation is equal to 0.
(df/dx) = 0
f(x) = x² + 6x + 8
(df/dx) = 2x + 6
At the vertex
(df/dx) = 2x + 6 = 0
2x = -6
Divide both sides by 2
(2x/2) = (-6/2)
x = -3
We then insert this into the equation to get the corresponding f(x) value.
f(x) = x² + 6x + 8
f(-3) = (-3)² + 6(-3) + 8
= 9 - 18 + 8
= -1
Hence, the vertex is at point (-3, -1)
And since the axis of symmetry has to pass through the vertex,
The axis of symmetry is x = -3
Hope this Helps!!!
Answer:
the last one my brother helped me answer this for u
Answer:
they are both true I guess. I just need points to get more answers. hopefully you find the right answer
Answer:
A:(-2,-3)
B:(-4.009,1.018) And (-2,-3)
C:x≈0,1.61878812
Step-by-step explanation:
I found the equations
g(x)=e^x+1
p(x)=5/2x+2
f(x)=-2x-7
plugged it in on a graph found the answer to find g(x) all you need to do is know the parent function y=e^2(exponential) and I found where the lines intersect for part A and B and or p(x)=g(x) I did e^x+1=(5/2)x+2
