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Mnenie [13.5K]
3 years ago
15

Jordans have a rectangular garden. want to build a diagonal pathway across he garden. the length of pathway is 90 ft. width of g

arden is 5 times more than 2 times the length of garden. what is length of garden?
Mathematics
2 answers:
blondinia [14]3 years ago
4 0
So we see the pythagorean theorem
a^2+b^2=c^2
diagonal=c
width=a or b, pick one
width=a
legnth=b
width is 5 times more than 2 times legnth of garden
w=5(2legnth)
this doesn't make sense since the legnth is normally longer than the width, but we'll stick with that
w=5(2l)
w=10l
a=10b
(10b)^2+b^2=90^2
100b^2+b^2=8100
101b^2=8100
divide by 101
b^2=80.198 aprox 80.2
square root
8.95533
legnth of garden =8.96
to find width subsitue
w=10l
w=89.56

legnth=8.96
width=89.56
Vedmedyk [2.9K]3 years ago
3 0
P=2l+2w
w=5(2l)
45=10l
4.5=l
---------------
P=2l+2(5(2l))
P=2l+20l
P=22l
P=99
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7 0
2 years ago
what is te discontinuity of the function f(x) = the quantity of x squared plus 6x plus 8 all over x plus 4?
seropon [69]

Answer:

A hole at x=-4.

Step-by-step explanation:

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Solving the equation

x+4=0 for x:

Subtract 4 on both sides:

x=-4

So there is either a vertical asymptote or a hole at x=-4.

These are the kinds of discontinuities we can have for a rational function.

If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.

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(-4)^2+6(-4)+8

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0

Top and bottom are 0 when x=-4.

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We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.

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I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.

\frac{x^2+6x+8}{x+4}=\frac{(x+4)(x+2)}{x+4}=x+2

We we able to cancel out that factor that was giving us x=-4 is a zero.  

Therefore there is a hole at x=-4.

7 0
3 years ago
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