Need help if answer is right ill give 5 stars

What is the value of n in this equation? n+ 134 = 379 423 245 334

alexira [117]

Answer:

the answer to this question is 245

Step-by-step explanation:

n+134=379

-134 -134

n=245

5 0

3 years ago

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Which graph shows the solution to this system of inequalities x-3y>3 2x-y<4

butalik [34]

Answer:

Step-by-step explanation:

would be graph x

3 0

3 years ago

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You and your friend are comparing two loan options for a $165,000 house. Loan 1 is a 15-year loan with an annual interest rate o

Harlamova29_29 [7]

Answer:

No, he is wrong.

Step-by-step explanation:

Since, the total payment of a loan after t years,

$A=P(1+r)^t$

Where,

P = present value of the loan,

r = rate per period ,

n = number of periods,

Given,

P = $165,000,

In loan 1 :

r = 3% = 0.03, t = 15 years,

So, the total payment of the loan is,

$A_1 = 165000(1+0.03)^{15}=165000(1.03)^{15}\approx \$ 257,064.62$

In loan 2 :

r = 4% = 0.04, t = 30 years,

So, the total payment of the loan is,

$A_2 = 165000(1+0.04)^{30}=165000(1.04)^{30}\approx \$ 535,160.59$

Since, $A_1 < A_2$

Hence, total amount repaid over the loan will be less for Loan 1.

That is, the friend is wrong.

7 0

2 years ago

Jacob followed a recipe that requires 2 cups of water for ever 3 cups of flour. If he

Kazeer [188]

Answer:

he used 5 1/3 everything else is to low or high

7 0

3 years ago

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of

iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is $\\ P(z>0.48) = P(x>533.2) = 0.3156$

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a sample mean. The distribution for sample means follows a normal distribution with mean $\\ \mu$ and standard deviation $\\ \frac{\sigma}{\sqrt{n}}$ . Mathematically

$\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

For values of the sample $\\ n \ge 30$ , no matter the distribution the data come from.

And the variable z follows a standard normal distribution, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [1]

That is

$\\ z \sim N(0, 1)$

We have a variance of 3364. That is, a standard deviation of

$\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58$

The population mean is

$\\ \mu = 530$

The sample size is $\\ n = 75$

The sample mean is $\\ \overline{x} = 533.2$

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}$

$\\ z = \frac{3.2}{\frac{58}{8.66025}}$

$\\ z = \frac{3.2}{6.69726}$

$\\ z = 0.47780$

With this value of z we can consult a cumulative standard normal table (or use some statistic program) to find the cumulative probability for z (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

$\\ P(z$

However, in the question we are asked for $\\ P(z>0.48) = P(x>533.2)$ . As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

$\\ P(z>0.48) = 1 - P(z$

Thus

$\\ P(z>0.48) = 1 - 0.68439$

$\\ P(z>0.48) = 0.31561$

Rounding to four decimal places, we have

$\\ P(z>0.48) = 0.3156$

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) $\\ P(z>0.48) = P(x>533.2) = 0.3156$ .

5 0

3 years ago