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2 years ago

The midpoint of AB is M(7,-5). If the coordinates of A are (6,-7), what are the coordinates of B?

Mathematics

1 answer:

Virty [35]2 years ago

4 0

Answer:

_____________________

a(6,-7) m(7,-5) letb(p,q)

Now,

Let a(6,-7) be x1 ,y1

Let b(p,q) be x2,y2

x,y = (7,-5)

Using Mid point Formula,

x = x1+x2 y= y1+y2

_____ , _____

2 2

7 = 6+p -5 = -7+q

___ , ____

2 2

or, 7×2=6+p , -5×2= -7+q

or, 14=6+p , -10= -7+q

or, p=14-6 , q= -7+10

p=8 , q= 3

Step-by-step explanation:

So , The coordinate of B(8,3)

Thank you

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2 years ago

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emmasim [6.3K]

The recursive formula for given sequence is: $a_n = a_{n-1}-7$

And the terms will be expressed as:

$a_1 = 11\\a_2 = a_{2-1} - 7 \\a_2= a_1 - 7\\a_2 = 11- 7\\a_2 = 4\\a_3 = a_{3-1} - 7 \\a_3= a_2 - 7\\a_3 = 4 - 7\\a_3 = -3\\a_4 = a_{4-1} - 7 \\a_4= a_3 - 7\\ a_4= -3 - 7\\a_4 = -10\\a_5 = a_{5-1} - 7 \\a_5= a_4 - 7\\a_5 = -10 - 7\\a_5 = -17\\$

Step-by-step explanation:

First of all, we have to determine if the given sequence is arithmetic sequence or geometric. For that purpose, we calculate the common difference and common ratio

Given sequence is:

11,4,-3,-10,-17...

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$a_1 = 11\\a_2 = 4\\a_3 = -3\\So,\\d = a_2 - a_1 = 4-11 = -7\\d = a_3-a_2 = -3-4 = -7$

As the common difference is same, given sequence is an arithmetic sequence.

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Hence,

The recursive formula for given sequence is: $a_n = a_{n-1}-7$

And the terms will be expressed as:

Keywords: arithmetic sequence, common difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

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