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luda_lava [24]
3 years ago
10

The midpoint of AB is M(7,-5). If the coordinates of A are (6,-7), what are the coordinates of B?

Mathematics
1 answer:
Virty [35]3 years ago
4 0

Answer:

_____________________

a(6,-7) m(7,-5) letb(p,q)

Now,

Let a(6,-7) be x1 ,y1

Let b(p,q) be x2,y2

x,y = (7,-5)

Using Mid point Formula,

x = x1+x2 y= y1+y2

_____ , _____

2 2

7 = 6+p -5 = -7+q

___ , ____

2 2

or, 7×2=6+p , -5×2= -7+q

or, 14=6+p , -10= -7+q

or, p=14-6 , q= -7+10

p=8 , q= 3

Step-by-step explanation:

So , The coordinate of B(8,3)

Thank you

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Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

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In order to make the leading co-efficient is =1, we multiply each term with -3.

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Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

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square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

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Subtracting 21 to both sides:

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Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

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