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2 years ago

Need help with this pls asap

Mathematics

1 answer:

Bezzdna [24]2 years ago

5 0

Need help asap beds helpbasap plzzzzzz need help asp

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Mógłby mi ktoś to obliczyć? Bardzo proszę ^^

statuscvo [17]

Answer:

I'm sorry but I don't understand what language this is.

Step-by-step explanation:

If you could say it in English maybe I could help :)

7 0

3 years ago

Kylie starts with $145 in her piggy bank. Each month she adds $20.

djverab [1.8K]

Kylie's first month collection, a1= $ 145

Second month collection , a2= $145+ 20

Third month collection, a3 = $145 +2*20

so for n months collection = an-1+20

We get an= 20 + an-1 and a1=145

4 0

3 years ago

Use the intermediate value theorem to determine whether the polynomial function has a real zeros between the given integers.

zavuch27 [327]

$f(1)=-5\cdot1^4+8\cdot1^3+6\cdot1+1=-5+8+6+1=10\\
f(2)=-5\cdot2^4+8\cdot2^3+6\cdot2+1=-80+64+12+1=-3\\\\
f(1)>0\\
f(2)$
It does.

3 0

3 years ago

Write the limit definition of a function of x

ollegr [7]

Answer:

the limit of a function is a fundamental concept in calculus and analysis concerning the behavior of that function near a particular input.

Step-by-step explanation:

7 0

3 years ago

4. A statistician working for the National Basketball Association supplies the television announcers with interesting statistics

Sonbull [250]

Answer: 0.038

Step-by-step explanation:

Given: Total games : n= 375

Number of games won by the team that was winning the game at the end of the third quarter. = 300

The proportion (p) of the team that was winning the game at the end of the third quarter: $p=\dfrac{300}{375}=0.8$

Critical z-value for 90% confidence: z* = 1.645

Margin of error = $z^*\sqrt{\dfrac{(1-p)p}{n}}$

The margin of error in a 90% confidence interval estimate of p $=1.645\sqrt{\dfrac{0.2\times0.8}{300}}\\= 1.645\times\sqrt{0.00053333}\\\\=1.645\times0.0231\\\\=0.0379995\approx$$0.038$

Hence, the required margin of error = 0.038

7 0

3 years ago