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Marina86 [1]
3 years ago
12

If you traded 6 cookies for m&ms, how many m&ms do you have?

Chemistry
2 answers:
Ede4ka [16]3 years ago
7 0

Answer:

Explanation:

6

larisa [96]3 years ago
6 0

Answer:

probably like 4 bags of m and ms lol

Explanation:

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How many joules of heat is lost when a 64 g piece of copper cools from 375 oC to 26 oC? The specific heat of copper is 0.38 J/go
Svetlanka [38]

Answer: 8500 J lost or -8500 J

Explanation:

q=cmt

t=375-26

t=349

q=0.38(64)(349)

q=8487.68 J

Answer must have 2 sig figs, which means it rounds to 8500 J.

7 0
3 years ago
8 l of water at 19 ∘c are mixed with 1.1 l of water at 47 ∘c in an insulated container. what is the final temperature of the sys
stepladder [879]
1692.9 is the answer


5 0
3 years ago
What is the nature of the SE-CI bond in molecule of selenium chloride ( SeCI3) if the electronegativity value of selenium is 2.5
blondinia [14]

3.2-2.5 = 0.7 pretty small difference

7 0
2 years ago
How many grams of ethanol c2h5oh can be made by the fermentation of 1150 g of glucose?
ozzi
Answer is: 588.15 <span>grams of ethanol.
</span>Chemical reaction: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂.
m(C₆H₁₂O₆) = 1150 g.
n(C₆H₁₂O₆) = m(C₆H₁₂O₆) ÷ M(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 1150 g ÷ 180.16 g/mol.
n(C₆H₁₂O₆) = 6.38 mol.
From chemical reaction: n(C₆H₁₂O₆) : n(C₂H₅OH) = 1 : 2.
n(C₂H₅OH) = 12.76 mol.
m(C₂H₅OH) = 12.76 mol · 46.07 g/mol.
m(C₂H₅OH) = 588.15 g.
5 0
3 years ago
How many atoms of mercury are present in 3.4 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc?
maks197457 [2]

Answer:

             1.37 × 10²³ Atoms of Mercury  

Solution:

Step 1: Calculate Mass of Mercury using following formula,

                               Density  =  Mass ÷ Volume

Solving for Mass,

                               Mass  =  Density × Volume

Putting values,

                               Mass  =  13.55 g.cm⁻³ × 3.4 cm³                ∴ 1 cm³ = 1 cc

                               Mass  =  46.07 g

Step 2: Calculating number of Moles using following formula;

                               Moles  =  Mass ÷ M.mass

Putting values,

                               Moles  =  46.07 g ÷ 200.59 g.mol⁻¹

                               Moles  =  0.229 mol

Step 3: Calculating Number of Atoms using following formula;

                               Number of atoms  =  Moles × 6.022 ×10²³

Putting value of moles,

                               Number of Atoms  =  0.229 mol × 6.022 × 10²³

                              Number of Atoms  =  1.37 × 10²³ Atoms of Hg

8 0
3 years ago
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