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4 years ago

Compare the first ionization energy of sodium to that of potassium

Chemistry

1 answer:

stellarik [79]4 years ago

3 0

Answer:

Sodium is higher than Potassium in thesame group

Explanation:

Sodium and potassium are the elements present in the first group of the periodic table. In group, atomic size increases from top to bottom this implies that even atomic radius increases. This causes less attraction force by nucleus on the electrons of outermost orbit of the atom and hence reduces the first ionisation energy, which is the energy required to remove the electron from the outermost orbit of an atom. So, as potassium is below sodium in the group, sodium has greater ionisation energy than potassium

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Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is _______ , and the chem

Kisachek [45]

Answer:

Hello my Friend! The answer is: Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is +3 , and the chemical formula of the compound is Mn2O3.

Explanation:

Manganese can have two oxidation states: +2 and +3, but in this case, the "(III)" indicates that in this compound, the state of oxidation is +3.

7 0

3 years ago

Read 2 more answers

While doing a lab a student found the density of a piece of pure aluminum to be 2.85 g/cm3 the accepted value for the density of

____ [38]

Answer:

THE PERCENT ERROR IS 5.55 %

Explanation:

To calculate the percent error, we use the formula:

Percent error = Found value - accepted value / accepted value * 100

Found value = 2.85 g/cm3

Accepted value = 2.70 g/cm3

Solving for the percent error, we have:

Percent error = 2.85 g/cm3 - 2.70 g/cm3 / 2.70 g/cm3 * 100

Percent error = 0.15 / 2.70 * 100

Percent error = 0.05555 * 100

Percent error = 5.55 %

In conclusion, the percent error is 5.55 %

3 0

4 years ago

What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?

kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $Al(OH)_3$ = 0.610 g

Molar mass of $Al(OH)_3$ = 78 g/mol

$\text{Number of moles}=\frac{0.610g}{78g/mol}$

Number of moles of $Al(OH)_3$ = 0.0078 moles

The reaction between $Al(OH)_3$ and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

$Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O$

By Stoichiometry,

1 mole of $Al(OH)_3$ reacts with 3 moles of HCl

So, 0.0078 moles of $Al(OH)_3$ will react with $\frac{3}{1}\times 0.0078$ = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

$0.0234moles=\frac{\text{Given mass}}{36.5g/mol}$

Mass of HCl required will be = 0.8541 grams

3 0

3 years ago

Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat

Sidana [21]

Answer:

D) 2, 4, and 5

Explanation:

In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.

If heat is absorbed in a reaction, that reaction is endothermic.

Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.

5 0

4 years ago

The cells of a tomato contain mostly an aqueous solution of sugar and other substances. If a typical tomato freezes at -2.5 °C,

DIA [1.3K]

Answer:

1.35 m

Explanation:

We can solve this problem by using the freezing point depression formula:

ΔT = Kf * m * i

Where:

ΔT is the temperature difference between the freezing point of the pure solvent (water) and the solution. In this case it is (0 °C - -2.5 °C = 2.5 °C).

Kf is the cryoscopic constant, for water it is 1.853 °C*kg/mol.

m is the molality.

i is the van't Hoff factor, as sugar does not dissociate in water, it has a value of 1.

We input the data:

2.5 °C = 1.853 °C*kg/mol * m * 1

And solve for m:

m = 1.35 m

6 0

3 years ago