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3 years ago

Fe2o3(s)+3h2(g)→2fe(s)+3h2o(l) Calculate the mass of H2O

Chemistry

1 answer:

777dan777 [17]3 years ago

7 0

Answer:

mass of H₂O = 54.06 g

Explanation:

balanced chemical equation

Fe₂O₃(s) + 3H₂(g) → 2Fe(s) + 3H₂O(l)

given data

moles of H₂O = 3 mol

mas of H₂O = ?

Molar mass of H₂O = 18.02 g/mol

we find the mass of H₂O by:

mass of H₂O = moles × molar mass

mass of H₂O = 3 mol × 18.02 g/mol

mass of H₂O = 54.06 g

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What is the correct iupac name of CH3-CH2-CH2CHO ?

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the correct IUPAC name of the compound is 1-Butanal.

<h3>What are IUPAC names?</h3>

It is a system of naming organic compounds based on the longest carbon-to-carbon single bonds. It does not matter whether these longest chains are continuous or in a ring.

Thus, when the compound with the chemical formula, CH3-CH2-CH2CHO is considered. The longest carbon-to-carbon chain is 4. The 1st carbon carries a functional group known as an aldehyde.

Aldehydes are equipped with the carbonyl group and have the general formula R−CH=O. They are also sometimes referred to as formyl.

Aldehydes are named after their parent alkane chains with a slight modification. The 'e' is replaced with 'al'

The aldehyde in this case has four carbons. This means that the parent alkane is Butane. Therefore, the name of the compound will be 1-Butanal.

More on IUPAC names can be found here: brainly.com/question/16631447

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2 years ago

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2 years ago

What is the heat of reaction (AH) of the<br> following?<br> C(s) + O2 (g) --> CO2 (g)

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3 years ago

1. A gas having the following composition is burnt under a boiler with 50% excess air.

jeka94

The composition of the stack gas are :

$CH_4$ = 0.8713

$C_3H_8$ = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of $CH_4$ : 70% of 100 g = 70 g

Mass of $C_3H_8$ : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of $CH_4$ : $\frac{70 g}{16.04 g/mol}$ = 4.3 mole