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PilotLPTM [1.2K]
2 years ago
5

How does the author support the statement that the laws of stratigraphy help

Biology
2 answers:
adell [148]2 years ago
8 0
B. By using specific examples of inferences that could be made using two laws of stratigraphy
aleksandr82 [10.1K]2 years ago
4 0

Answer: B, i took the flocabulary quiz

Explanation:

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When utilizing a KO mouse model, you want to see if introducing the dystrophin gene can rescue the DMD mouse model. Propose a me
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<h2>CRISPR/Cas9</h2>

Explanation:

CRISPR can be used to reintroduce dystrophin back into the KO mouse

  • CRISPR stands for Clustered Regularly Interspaced Short Palindromic Repeats and is used to for gene editing
  • CRISPR/Cas-mediated genome editing has been shown to permanently correct DMD mutations and restore dystrophin function in mouse models
  • Germline editing by injecting zygotes with CRISPR/Cas9 editing component was first done in mdx mice by correcting the mutated exon 23
  • Postnatal editing of mdx mice was then achieved using recombinant adeno-associated virus to deliver CRISPR/Cas9 genome editing components and correct the dystrophin gene by skipping or deleting the mutated exon 23 in vivo
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3 years ago
How was osmosis involved in causing seizures?​
olga_2 [115]

Answer:

Seizures is most triggered by dehydration

6 0
2 years ago
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
Agata [3.3K]

Answer:

2,855 is the size of the colony of mosquitoes after 4 ​days.

Explanation:

The law of uninhibited growth is given as:

A=A_o\times e^{k\times t}

A_o= Original amount

A = Amount after time t

k = Positive constant repressing the rate of growth

We are given with:

Original population of mosquitoes = 1000

Population of mosquitoes after 1 day =1300

t = 1 day

1300=1000\times e^{k\times 1 day}

k = 0.2623 day^{-1}

Population size of mosquitoes after 4 days

A_o=1000, k= 0.2623 day^{-1}

A =? , t = 4 days

A=1000\times e^{ 0.2623 day^{-1}\times 4 days}

A =2,855.36 ≈ 2,855 mosquitoes

2,855 is the size of the colony of mosquitoes after 4 ​days.

5 0
3 years ago
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Beriman kepada para rasul akan mendapat kebahagiaan di dunia dan
olga2289 [7]

Answer:

Explanation:

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Consider a cell that requires much more ribose5‑phosphate than NADPH. The cell needs ribose 5‑phosphate but has a relatively hig
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B- Most of the glucose 6-phosphate enters the pentose phosphate pathway.

Explanation:

Since the cell requires much more ribose 5- phosphate than NADPH, then it would lead the glucose 6-phosphate down the oxidative phosphate pathway to create ribulose 5-phosphate, which can be isomerized to ribose 5-phosphate depending on the cell state.

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3 years ago
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