Please help a brotha out so I can get ungrounded! Will give Brainlyest!
1 answer:
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Answer:
an isosceles right triangle
Step-by-step explanation:
The square of the length of a side can be found from the distance formula:
d^2 = (x2-x1)^2 +(y2-y1)^2
The square of the length of WX is ...
WX^2 = (-3-(-10))^2 +(-1-4)^2 = 49+25 = 74
The square of the length of XY is ...
XY^2 = (-5-(-3))^2 +(11-(-1))^2 = 4 +144 = 148
The square of the length of YW is ...
YW^2 = (-10-(-5))^2 +(4 -11)^2 = 25 +49 = 74
The sum of the squares of the short sides is equal to the square of the long side, so this is a right triangle. The squares of the short sides are equal, so this is an isosceles right triangle.
For this case we have the following system of equations:
From the first equation we clear "x":
We substitute in the second equation:
We apply distributive property:
We add similar terms:
We add 65 to both sides:
We divide between 22 on both sides:
We look for the value of the variable "x":
Thus, the solution of the system is:
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