Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
Answer:
Mark Brainllest
Step-by-step explanation:
- A) −9 − 7n + 16n B) 9(n − 9) Eliminate C) n − 9 + 8n D) 9n − 9 ... The expression is not equivalent to other three is 9(n-9) . Option (B) is correct .
Answer:
34%
Step-by-step explanation:
100 x 0.34 ( or 34%)
= 34
Hope this helps. I switch the x and y so its easier to solve.
city X temperature is <u>-30</u>
city Y temperature is <u>-26.1</u>
city Z temperature is <u>-23.3</u>
the City that is the coldest is <u>city X</u>
