By the confront theorem we know that the limit only exists if both lateral limits are equal
In this case they aren't so we don't have limit for x approaching 2, but we can find their laterals.
Approaching 2 by the left we have it on the 5 line so this limit is 5
Approaching 2 by the right we have it on the -3 line so this limit is -3
Think: it's approaching x = 2 BUT IT'S NOT 2, and we only have a different value for x = 2 which is 1, but when it's approach by the left we have the values in the 5 line and by the right in the -3 line.
The expansion of the expression (x + 2y)² is x² + 4xy + 4y².
<h3>How to illustrate the information?</h3>
The given expression is (x + 2y)². The expansion of the expression will be:
(x + 2y)²
= (x + 2y)(x + 2y)
= x² + 2xy + 2xy + 4y².
= x² + 4xy + 4y²
The expansion is x² + 4xy + 4y².
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77 and 791 are both relatively prime numbers
