Estimate 5÷10/11 to the nearest whole number
2 answers:
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Answer:
<h2>m∠EFG = 126°</h2><h2>m∠GFH = 54°</h2>Step-by-step explanation:
If ∠EFG and ∠GFH are a linear pair, then m∠EFG + m∠GFH = 180°
(look at the picture).
We have
m∠EFG = 5n + 16
m∠GFH = 2n + 10
Substitute:
(5n + 16) + (2n + 10) = 180 <em>combine like terms</em>
(5n + 2n) + (16 + 10) = 180
7n + 26 = 180 <em>subtract 26 from both sides</em>
7n + 26 - 26 = 180 - 26
7n = 154 <em>divide both sides by 7</em>
7n/7 = 154/7
n = 22
Insert the value of n into expressions that specify angle measures:
m∠EFG = 5n + 16 → m∠EFG = 5(22) + 16 = 110 + 16 = 126°
m∠GFH = 2n + 10 → m∠GFH = 2(22) + 10 = 44 + 10 = 54°
