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2 years ago

Write the following equation in slope-intercept form 5+ 2y = 4

Mathematics

2 answers:

frosja888 [35]2 years ago

8 0

Answer:

Slope-intercept form :

y = mx + b, where m = slope and b = intercept

$5x + 2y = 4 \\ 2y = - 5x + 4 \\ y = \frac{ - 5}{2} x + \frac{4}{2} \\ \boxed{y = \frac{ - 5}{2}x + 2 }$

Slope = -5/2 = -2.5
Intercept = (0,2)

Ksenya-84 [330]2 years ago

7 0

I hope this’ll help shjsjskskkalala

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Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat

likoan [24]

F+G:

$F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}$

Then, add the elements that occupy the same position:

$H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}$

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$H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}$

So, we find the element at address h31:

$H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}$

In this case, position h31 is - 8.0

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