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2 years ago

What is the solution to this matrix?

Mathematics

1 answer:

Ne4ueva [31]2 years ago

5 0

Step-by-step explanation:

b I believe it is b hope that helps

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Write this decimal as a fraction. 0.45 repeating

sergij07 [2.7K]

Answer:

= 45/99 (since 45 is the repeating part of the decimal and it contains 2 digits). We can divide both the top and bottom parts by 9 to find that 0.454545… = 45/99 = 5/11.

Step-by-step explanation:

Hope this helps!

8 0

3 years ago

Read 2 more answers

Isolating a variable in two equations is easiest when one of them has a coefficient 1.

Tomtit [17]

Answer:

Option C.

Step-by-step explanation:

The given equations are

$3A-B=5$

$2A+3B=-4$

We need isolate one of the variables, such that it appears by itself on one side of the equation.

Isolating a variable in two equations is easiest when one of them has a coefficient 1.

In equation 1, coefficient of B is 1. So, we can easily isolate one of the variables.

The equation is

$3A-B=5$

Subtract 3A from both sides.

$-B=5-3A$

Multiply both sides by -1.

$B=3A-5$

Therefore, the correct option is C.

6 0

3 years ago

URGENT PLEASE HELP ME

krek1111 [17]

a) & b) is yes, c) is no. hope you have a good day

5 0

3 years ago

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Solve for Z<br><br> (This should be another easy question, + there are answers you can choose from)

Delvig [45]

Answer:

Z = 6

Step-by-step explanation:

Z/12 = Cos(60°)

Z/12 = 1/2

8 0

2 years ago

Read 2 more answers

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0

2 years ago