What is the solution to this matrix?

Laura's job is 4 1/2 miles away. If she starts walking to her job at 9:00 a.m. and is scheduled to start working at 11:00 a.m.,

irina [24]

Answer:

<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Distance from Laura's home to her job = 4 1/2 miles

Time when Laura starts to walk to her job : 9:00 a.m.

Time when Laura is scheduled to start working : 11:00 a.m.

2. Will she arrive at her job on time?

Time Laura has to complete the distance from her home to her job = 2 hours (11 -9)

Speed that Laura need to walk to arrive to her job on time = Distance from Laura's home to her job/Time Laura has to complete the distance from her home to her job

Speed that Laura need to walk to arrive to her job on time = 4 1/2 miles/2 hours = (4 1/2)/2 = (9/2)/2 = 9/2 * 1/2 = 9/4 = 2 1/4

Speed that Laura need to walk to arrive to her job on time = 2 1/4 miles per hour.

<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>

7 0

3 years ago

I believe this is goodbye i hope i helped u guys.

jeyben [28]

Answer:

goodbye??? what're you going to bed? you alr my dude?

Step-by-step explanation:

5 0

3 years ago

This one and thats it.

4vir4ik [10]

Answer:

you just take the data given and put it on the graph

7 0

3 years ago

Let X denote the number of flaws along a 100-m reel of magnetic tape (an integer-valued variable). Suppose Zdenote the number of

Lemur [1.5K]

Answer:

a) $P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)$

$P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)$

And we can find this probability like this:

$P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728$

b) $P(X \leq 30)= P(X$

And using the z score we got:

$P(X$

c) $P(X$

And if we use the continuity correction we got:

$P(X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Continuity correction means that we need to add and subtract 0.5 before standardizing the value specified.

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(25,5)$

Where $\mu=25$ and $\sigma=5$

Part a

For this case we want to find this probability:

$P(20 \leq X \leq 30) = P(20-0.5 \leq X \leq 30+0.5)$

And if we use the z score given by:

$z =\frac{x-\mu}{\sigma}$

We got this:

$P(19.5 \leq X \leq 30.5) = P(\frac{19.5-25}{5} \leq Z \leq \frac{30.5 -25}{5})=P(-1.1 \leq Z \leq 1.1)$

And we can find this probability like this:

$P(-1.1 \leq Z \leq 1.1)= P(Z\leq 1.1) -P(Z\leq -1.1) = 0.864-0.136= 0.728$

Part b

For this case we want this probability:

$P(X \leq 30)$

And if we use the continuity correction we got:

$P(X \leq 30)= P(X$

And using the z score we got:

$P(X$

Part c

For this case we want this probability:

$P(X$

And if we use the continuity correction we got:

$P(X$

3 0

3 years ago

On an architect's drawing of the floor plan for a house, 1 inch represents 3 feet if a room is represented on the floor plan by

r-ruslan [8.4K]

3.5×3=10.5 ft
5×3=15
15×10.5=157.5 square feet

5 0

3 years ago