Answer:
a < -30/31
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
7a + 42 + 8 < -10 + 9a - 64a
<u>Step 2: Solve for </u><em><u>a</u></em>
- Combine like terms (a): 7a + 42 + 8 < -10 - 55a
- Combine like terms: 7a + 50 < -10 - 55a
- [Addition Property of Equality] Add 55a on both sides: 62a + 50 < -10
- [Subtraction Property of Equality] Subtract 50 on both sides: 62a < -60
- [Division Property of Equality] Divide 62 on both sides: a < -30/31
Here we see any number <em>a</em> less than -30/31 would work as a solution to the inequality.
Answer:
law of cosines states c^2=a^2+b^2-2abc
b^2=26^2+24^2-2(26×24)cos 134°
b^2=676+576-1248cos134°
cos134= -0.6946
b^2=1252-12(-0.6946)
12×(-0.6946)= -8.3352
b^2=1252-(-8.3352)
b^2=1252+8.3352
b^2=1260.33
b=√1260.33
b=35.50
Answer:
(x+4)
Step-by-step explanation:
The
correct answer is:
TrueExplanation:
1.
(Straightforward)
2.
(log to base of itself is always 1)
3.
(Using log power property)
Hence the correct option is True.
