Equation of a line that is perpendicular to the line
and contains the point (-9,0). is ![y=-9x-81](https://tex.z-dn.net/?f=y%3D-9x-81)
Step-by-step explanation:
We need to find the equation of a line that is perpendicular to the line
and contains the point (-9,0).
Finding slope
Since the lines are parallel, the slopes will be -1/slope 1
The equation given is in slope-intercept form:
where m is slope.
Comparing with given equation
the slope = 1/9
So, slope of required line is: -9
Finding y-intercept
To find y-intercept we use point (-9,0) and slope -9
Putting values:
![y=mx+b\\0=-9(-9)+b\\0=81+b\\b=-81](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5C%5C0%3D-9%28-9%29%2Bb%5C%5C0%3D81%2Bb%5C%5Cb%3D-81)
So, y-intercept of required line is -81
Finding equation of required line:
Slope m = -9, y-intercept b = -81
Putting values
![y=mx+b\\y=-9x-81](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5C%5Cy%3D-9x-81)
So, equation of a line that is perpendicular to the line
and contains the point (-9,0). is ![y=-9x-81](https://tex.z-dn.net/?f=y%3D-9x-81)
Keywords: Equation of line using Slope
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