Ask question

Ask question

All categories

3 years ago

5

Can someone explain me how do i do (ii)?

1 answer:

Varvara68 [4.7K]3 years ago

6 0

Answer:

(only ii right?)

Since we have the total number is 360° and our section is 72°, we know that the percentage of students who choose the cinema should be the number that we have divided to the total amount and then multiply the result by 100 ( it's fine if you write 100%, but when you actually calculate it, it's only 100, not 100%):

(72/360) . 100 = 20%

You might be interested in

Which pair of words is the ODD one out. A. sister-brother, B. wife-husband, C. teacher-student or D. princess-prince

wel

Answer:

C. teacher-student

Step-by-step explanation:

the pattern is girl, boy, girl boy, and teacher and student don't have a gender connection

8 0

3 years ago

What’s the answer to this

ryzh [129]

Answer:

see below

Step-by-step explanation:

The graph extends to the left more or less horizontally, approaching the line y=3. The only choice that expresses that is the third one.

7 0

3 years ago

¿Cuántas esferas hay en la figura 20?

scoundrel [369]

Answer:

418

Step-by-step explanation:

fig 2 = fig 1 + 5

fig 3 = fig 2 + 7 or fig 1 +5+7 16

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

4+5+7+9+11+13+15+17+18+19+21+23+25+27+29+31+33+35+37+39

8 0

3 years ago

What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n

Yakvenalex [24]

Answer:

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

$-2x^{2} +y=-5$ ----> equation A

$y=-3x^{2} +5$ -----> equation B

solve by substitution

substitute equation B in equation A

$-2x^{2} +(-3x^{2} +5)=-5$

solve for x

$-5x^{2} +5=-5$

$-5x^{2}=-10$

$x^{2}=2$

$x=\pm\sqrt{2}$

<em>Find the value of y</em>

$y=-3x^{2} +5$

For $x=\sqrt{2}$ ----> $y=-3(\sqrt{2})^{2} +5=-1$

For $x=-\sqrt{2}$ ----> $y=-3(-\sqrt{2})^{2} +5=-1$

therefore

The solutions are

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

8 0

3 years ago

Read 2 more answers

Vesna [10]

A(n)=a+(n-1)d
A(40)= -1+(40-1)-4
A(40)= -1+39(-4)
A(40)= -1+(-156)
A(40)= -157

4 0

2 years ago