There you go!!! Answer is at the very bottom. let me know if you have questions
A square has 4 sides of equa length
the perimiter is 4 times the side, or P=4s where s=length of 1 side
the area is length times witdth, but since the length=width, area=s² where s is the length of one side
so express A=s² in terms of P when P=4s
solve for s first in P=4s
P=4s
divide both sides by 4
subsitute
for s in the other eqaution
in terms of the perimiter, the area is
.3 = 3/10
.5 = 1/2
.05 = 1/20
.25 = 1/4
The answer is here written
Answer: see below
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: y = a(x - h)² + k where
- "a" is the vertical stretch (positive = min [U], negative = max [∩])
- (h, k) is the vertex
- Axis of Symmetry is always: x = h
- Domain is always: x = All Real Numbers
- Range is y ≥ k when "a" is positive or y ≤ k when "a" is negative
a) y = 2(x - 2)² + 5
↓ ↓ ↓
a= + h= 2 k= 5
Vertex: (h, k) = (2, 5)
Axis of Symmetry: x = h → x = 2
Max/Min: "a" is positive → minimum
Domain: x = All Real Numbers
Range: y ≥ k → y ≥ 5
b) y = -(x - 1)² + 2
↓ ↓ ↓
a= - h= 1 k= 2
Vertex: (h, k) = (1, 2)
Axis of Symmetry: x = h → x = 1
Max/Min: "a" is negative → maximum
Domain: x = All Real Numbers
Range: y ≤ k → y ≤ 2
c) y = -(x + 4)² + 0
↓ ↓ ↓
a= - h= -4 k= 0
Vertex: (h, k) = (-4, 0)
Axis of Symmetry: x = h → x = -4
Max/Min: "a" is negative → maximum
Domain: x = All Real Numbers
Range: y ≤ k → y ≤ 0
d) y = 1/3(x + 2)² - 1
↓ ↓ ↓
a= + h= -2 k= -1
Vertex: (h, k) = (-2, -1)
Axis of Symmetry: x = h → x = -2
Max/Min: "a" is positive → minimum
Domain: x = All Real Numbers
Range: y ≥ k → y ≥ -2