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MAXImum [283]
3 years ago
7

How to solve this problem

Mathematics
1 answer:
rodikova [14]3 years ago
3 0
\bf \textit{circumference of a circle}\\\\
C=2\pi r\quad 
\begin{cases}
r=radius\\
-----\\
r=10
\end{cases}\implies C=2\pi 10\implies \boxed{C=20\pi }\\\\
-------------------------------\\\\

\bf \textit{let's converte 1km to inches}
\\\\\\
km\cdot \cfrac{1000m}{km}\cdot \cfrac{100cm}{m}\cdot \cfrac{in}{2.54cm}\implies \cfrac{1000\cdot 100\cdot in}{2.54}\approx 39370.079\ in\\\\
-------------------------------\\\\
\textit{how many times does }20\pi \textit{ go into }39370.079?\implies \boxed{\cfrac{39370.079}{20\pi }}
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8 0
3 years ago
The sum of a number and its square is 182. Find the number.
Mars2501 [29]

Answer:

13 and -14 satisfy this condition

Step-by-step explanation:

Let's represent that number as x

and the square of x is x^2

So,

x + x^2 = 182

Subtract 182 from both sides

x + x^2 - 182 = 182 - 182

x + x^2 - 182 = 0

rearrange the quadratic equation

x^2 + x -182 = 0

let's use the quadratic formula

\frac{-b+\sqrt{b^2-4ac} }{2a}       or      \frac{-b-\sqrt{b^2-4ac} }{2a}

a = 1, b = 1, c = -182

\frac{-1+\sqrt{1^2-4*1*(-182)} }{2*1}       or     \frac{-1-\sqrt{1^2-4*1*(-182)} }{2*1}

\frac{-1+\sqrt{1+728} }{2}      or         \frac{-1-\sqrt{1+728} }{2}

\frac{-1+\sqrt{729} }{2}            or    \frac{-1-\sqrt{729} }{2}

\frac{-1+{27} }{2}     or    \frac{-1-{27} }{2}

\frac{26}{2}     or    \frac{-28}{2}

13 or    - 14

Lets check

13 + 13^2 = 13 + 169

= 182

Also,

-14 + (-14^2) = -14 + 196

= 182

8 0
3 years ago
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