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3 years ago

15

Can someone please help me?

1 answer:

Norma-Jean [14]3 years ago

6 0

Answer:

its a acute angle........

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Andrea, Justin, and Virginia went to an office supply store. Andrea bought 6 pencils, 7 markers, and 8 erasers. Her total was $1

olga2289 [7]

Answer:

$x=0.25\,,\,y=1.75\,,\,z=0.25$

Step-by-step explanation:

Let $x,y,z$ denotes number of pencils, markers, erasers respectively.

For Andrea:

$6x+7y+8z=15.75\,\,\,(i)$

For Justin:

$6x+8y+5z=16.75\,\,\,(ii)$

For Virginia:

$5x+5y+7z=11.75\,\,\,(iii)$

On subtracting equations (i) and (ii), we get

$(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z$

Put $y=1+3z$ in equation (i)

$6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)$

Put $y=1+3z$ in equation (iii)

$5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)$

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

$5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25$

Put $z=0.25$ in equation $y=1+3z$

$y=1+3(0.25)=1.75$

Put $y=1.75\,,\,z=0.25$ in equation (i)

$6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25$

8 0

3 years ago

Please <br> Helppppp :) :)

harkovskaia [24]

Answer:

mm the answer would be

Step-by-step explanation:

1 may be

5 0

3 years ago

Read 2 more answers

The number of girls in a classroom is greater than the number of boys. There are more than girls. Write system of inequalities t

Fofino [41]

Answer:

Step-by-step explanation:

Required

Represent the relationship between population of girls and boys

From the question, we have that

$Boys = x\\Girls = y$

<em>Given that y is greater than x in the classroom;</em>

<em>One of the keywords in the given data is</em><em> "Greater than"</em>

The inequality to represent the system is the greater than sign;

In other words, >

Bringing x, y and > together to form a complete inequality; we have

$Girls > Boys$

Replace Girls with y and Boys with x

$y > x$

5 0

3 years ago

Expand each expression

matrenka [14]

Answer:

Option B - $\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Step-by-step explanation:

Given : Expression $\ln(\frac{4y^5}{x^2})$

To find : Expand each expression ?

Solution :

Using logarithmic properties,

$\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B$

and $\ln (AB)=\ln A+\ln B$

Here, A=4y^5 and B=x^2

$\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}$

$\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2$

$\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2$

Using logarithmic property, $\logx^a=a\log x$

$\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Therefore, option B is correct.

3 0

2 years ago

Read 2 more answers

Find the quotient .........

Nady [450]

1.75/9

hope thie helps

8 0

3 years ago

Read 2 more answers