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KIM [24]
3 years ago
15

Can someone please help me?

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

its a acute angle........

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Andrea, Justin, and Virginia went to an office supply store. Andrea bought 6 pencils, 7 markers, and 8 erasers. Her total was $1
olga2289 [7]

Answer:

x=0.25\,,\,y=1.75\,,\,z=0.25

Step-by-step explanation:

Let x,y,z denotes number of pencils, markers, erasers respectively.

For Andrea:

6x+7y+8z=15.75\,\,\,(i)

For Justin:

6x+8y+5z=16.75\,\,\,(ii)

For Virginia:

5x+5y+7z=11.75\,\,\,(iii)

On subtracting equations (i) and (ii), we get

(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z

Put y=1+3z in equation (i)

6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)

Put y=1+3z in equation (iii)

5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25

Put z=0.25 in equation y=1+3z

y=1+3(0.25)=1.75

Put y=1.75\,,\,z=0.25 in equation (i)

6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25

8 0
3 years ago
Please <br> Helppppp :) :)
harkovskaia [24]

Answer:

mm the answer would be

Step-by-step explanation:

1 may be

5 0
3 years ago
Read 2 more answers
The number of girls in a classroom is greater than the number of boys. There are more than girls. Write system of inequalities t
Fofino [41]

Answer:

Step-by-step explanation:

Required

Represent the relationship between population of girls and boys

From the question, we have that

Boys = x\\Girls = y

<em>Given that y is greater than x in the classroom;</em>

<em>One of the keywords in the given data is</em><em> "Greater than"</em>

The inequality to represent the system is the greater than sign;

In other words, >

Bringing x, y and > together to form a complete inequality; we have

Girls > Boys

Replace Girls with y and Boys with x

y > x

5 0
3 years ago
Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

3 0
2 years ago
Read 2 more answers
Find the quotient .........
Nady [450]
1.75/9


hope thie helps
8 0
3 years ago
Read 2 more answers
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