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TEA [102]
3 years ago
14

Show your work and ill give you brainliest!!!

Mathematics
1 answer:
Rus_ich [418]3 years ago
4 0

Answer:

1) 36 and 2) 52

Step-by-step explanation:

1820/35=52

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Find S10 for -1 + -7 + -13 + -19
Alex777 [14]
First we find the common difference...to do this we subtract the first term from the second term. -7 - (-1) = -7 + 1 = -6

now we are going to find the 10th term
an = a1 + (n-1)*d <== formula for finding any term in arithmetic series
a1 = 1st term, d = common difference, n = term we want to find
now we sub
a10 = -1 + (10 -1) * -6
a10 = -1 + (9 * -6)
a10 = -1 - 54 
a10 = - 55

now we will find the sum
Sn = (n (a1+ an)) / 2 <== formula for finding the sum 
S10 = (10(-1 - 55))/2
S10 = (10(-56) / 2
S10 = -560/2
S10 = - 280

so the sum of the first 10 numbers is -280

4 0
3 years ago
Y=x+1 and y=-x-3 in graphing,Substitution,and elemination
marysya [2.9K]

\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\GRAPHING\ \text{(look at the picture)}\\\\y=x+1\\for\ x=0\to y=0+1=0\to(0,\ 1)\\for\ x=-1\to y=-1+1=0\to(-1,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=0\to(-3,\ 0)\\\\Solution:\ (-2,\ -1)


SUBSTITUTION\\\\\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\\text{substitute}\ y=-x-3\ \text{to the first equation}\\\\-x-3=x+1\ \ \ \ |+3\\-x=x+4\ \ \ \ |-x\\-2x=4\ \ \ \ |:(-2)\\x=-2\\\\\text{substitute the value of x to the second equation}\\\\y=-(-2)-3=2-3=-1\\\\Solution:\ (-2,\ -1)


ELIMINATION\\\\\underline{+\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right}\ \ \ |\text{add both sides of the equations}\\.\ \ \ \ 2y=-2\ \ \ \ |:2\\.\ \ \ \ \ \ y=-1\\\\\text{put the value of y to the first equation}\\\\-1=x+1\ \ \ \ |-1\\x=-2\\\\Solution:\ (-2,\ -1)

5 0
3 years ago
Solve for X. Please explain if possible.<br> -8 1/4x - 68 = -6.25x - 58
AleksandrR [38]

Answer:

X=-5

Step-by-step explanation:

Start by isolating the variable to one side. So from here we would add 68 to both sides. we will be left with -8 1/4x = -6.25x+10. Then add 6,25 to both sides to cancel on and get -2x=10. Divide both sides by -2 to get x=-5

8 0
3 years ago
What is the derivative of arcsin(6x)
schepotkina [342]
\bf sin^{-1}(6x)\\\\&#10;-----------------------------\\\\&#10;\textit{using the chain-rule}\implies \cfrac{d}{dx}\left[ sin^{-1}(6x) \right]\implies \cfrac{1}{\sqrt{1-(6x)^2}}\cdot 6\\\\ \cfrac{6}{\sqrt{1-36x^2}}
8 0
3 years ago
Can someone please tell me what to do for this?? Thank you :))
bezimeni [28]

take it and leave it somewhere u will forget about it and move on with ur life lol

5 0
3 years ago
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