we are given
A ball rolling down a hill was displaced 19.6 m
so,
![h=19.6m](https://tex.z-dn.net/?f=h%3D19.6m)
the final velocity was 5.00m/s
so, ![v=5m/s](https://tex.z-dn.net/?f=v%3D5m%2Fs)
Since, a ball rolling down a hill was displaced
so, we get
![u=0m/s](https://tex.z-dn.net/?f=u%3D0m%2Fs)
we can use kinematic equation formula
![v^2-u^2=2ah](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ah)
Here ,
v is final velocity
u is initial velocity
a is acceleration
h is height from which ball is dropped
now, we can plug our values
![5^2-0^2=2a(19.6)](https://tex.z-dn.net/?f=5%5E2-0%5E2%3D2a%2819.6%29)
![2a\left(19.6\right)=5^2](https://tex.z-dn.net/?f=2a%5Cleft%2819.6%5Cright%29%3D5%5E2)
![2a\left(19.6\right)=25](https://tex.z-dn.net/?f=2a%5Cleft%2819.6%5Cright%29%3D25)
................Answer
3.917≈3.9165
Or you mean 3.917≈4
13x−2/3x
=13x+(−2/3x)
Combine Like Terms:
=13x+(−2/3x)
=(13x+(−2/3x)
=37/3x
226,224.
If it takes 13 years to double the population of already 127,866, that means that it grows around 9836 people annually. 23-13 = 10, so multiply that by 9836, giving you 98,358 because thats the remaining years after the population doubles. So, 255,732, which is the doubled population after 13 years + 98,358, the population after the remaining 10 years =354,090, the population after 23 years.