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VashaNatasha [74]
3 years ago
7

Ryan scores 200 points more than twice what joseph scores in a video game. if ryan scores 1600 points, how many points does jose

ph score?
Mathematics
2 answers:
Gennadij [26K]3 years ago
6 0
I think it would be 700 points
I am Lyosha [343]3 years ago
3 0
Joseph scores _ points.

To find out the answer, we should come up with an equation.

The equation is (1600-200) ÷ 2

1600 - 200 is 1,400

1,400 divided by 2 is 700

So, Joseph scores 700 points.
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You do not need to flip the inequality sign when solving the following -5 ≤ 4r + 3.
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3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%
SVETLANKA909090 [29]

\huge \boxed{\mathbb{QUESTION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)

The remaining elements of the product matrix are found in the same way.

\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)

Simplify each element by multiplying the individual terms.

\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)

Now, sum each element of the matrix.

\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}

7 0
3 years ago
The one that said there should be a choose number of trial. the answer chose are greater or lesser
Alexeev081 [22]

Answer:

The first option is greater. The second option is more. The third option is 50%.

Step-by-step explanation:

Flipping a coin heads or tails expected probability is 50%. The more trials there are, the more accurate the actual probability will be.

Hope this helps!

6 0
3 years ago
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