What is the difference, if any, between a correlation statement and a causation statement?

PLEASE HELP I WILL MARK YOU BRAINLIEST

stira [4]

Answer:

1. 2448 do 612x4

2.she got $23 because he has four children and splits all do 72 divide by 4 and add 5 and thats ur answer

hope this helped

5 0

3 years ago

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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.

melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean for mail-order sales = $74.50

$\bar X_2$ = sample mean for internet sales = $84.40

$s_1$ = sample standard deviation for mail-order purchases = $17.25

$s_2$ = sample standard deviation for internet purchases = $21.25

$n_1$ = sample of sales receipts for mail-order purchases = 16

$n_2$ = sample of sales receipts for internet purchases = 9

Also, $s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} }$ = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by ( $\mu_1-\mu_2$ ).

Now, 99% confidence interval for ( $\mu_1-\mu_2$ ) is given by;

= $(\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_) \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}$

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

= $(74.50-84.40) \pm (2.807 \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})$

= [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0

3 years ago

Jen has 6 yards of fabric and wants to make a new dress and shorts she used 3 1/3 yards of the fabric on her new dress how much

kodGreya [7K]

Answer:

$2\frac{2}{3}\ yards$

Step-by-step explanation:

we know that

To find out how much fabric Jen has left for the shorts, subtract the yards of fabric used in her new dress from the total yards of fabric Jen has.

so

$6-3\frac{1}{3}$

Convert mixed number to an improper fraction

$3\frac{1}{3}=\frac{3*3+1}{3}=\frac{10}{3}$

substitute

$6-3\frac{1}{3}=6-\frac{10}{3}=\frac{8}{3}\ yards$

Convert to mixed number

$\frac{8}{3}\ yards=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}\ yards$

5 0

3 years ago

Solve: -4x-8x+17=23 check solution

Sveta_85 [38]

Answer:

x = -1/2

Step-by-step explanation:

To solve the equation, we first need to combine like terms:

$-12x+17=23$

Simplify further:

$-12x=6$

Divide by -12 on both sides to get:

$x = -\frac{1}{2}$

To check the solution, plug x back into the original equation and check if we get the correct answer:

$-4(-\frac{1}{2})-8(-\frac{1}{2})+17=23$

$2+4+17= 23$

$23=23$

Thus, it checks out and our answer is correct.

4 0

3 years ago

What is GE ? Enter your answer in the box.

harina [27]

Since ZY bisects GE and XY bisects EF, and both ZY and XY both bisect GF, then XY ~ ZE and ZY ~ XE.
Therefore ZE = XY = 5
And GE = 2× ZE (because bisected segments are = and therefore ×2 = long segment).
So GE = 2ZE = 2×5 = 10

6 0

3 years ago

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