To find the volume of a cone you use the formula "1/3 x 3.14 x r^2 x h". Plug the formula into the problem. 1/3 x 3.14 x 3.75^2 x 3.5 =51.51. Rounded to the nearest tenth is 51.5. Hope this helps!
Step-by-step explanation:
-1,6 is -1 left 6 up
1,-6 is 1 right -6 down
6,-1 is 6 right -1 down
You would plug in 3 for x, which gives you y = 10(3) + 2, and then you would use PEMDAS, which means you multiply 10 with 3 and then add two which is 32. Therefore y would equal 32. :D :D
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²