ANSWER:
u=4
EXPLANATION:
distribute the 2 and simplify.
Answer:
7w^3/5v
Step-by-step explanation:
42v^3w^4/30v^4w
42 = 6 * 7
30 = 6*5 , factor
6*7v^3w^4/6*5v^4w
6 is common, cancel
7v^3w^4/5v^4w
simplify w^4/w = w^3
v^3/v^4 = 1/v
therefore, 7w^3/5v is the answer
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
5/8 Jar
Step-by-step explanation:
I took the test...