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ioda
3 years ago
15

Find the distance between the two points. (9,7) and (-1,31)

Mathematics
1 answer:
Bond [772]3 years ago
5 0

Answer:

26 hope this helps

Step-by-step explanation:

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You divide 200 by 5 and you get 40.
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3 years ago
Solve for u 2(4u-9)=14<br> plzzzz <br> will give brailiest
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ANSWER:
u=4

EXPLANATION:
distribute the 2 and simplify.

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2 years ago
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Please help with this ASAP
uranmaximum [27]

Answer:

7w^3/5v

Step-by-step explanation:

42v^3w^4/30v^4w

42 = 6 * 7

30 = 6*5 , factor

6*7v^3w^4/6*5v^4w

6 is common, cancel

7v^3w^4/5v^4w

simplify w^4/w = w^3

v^3/v^4 = 1/v

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7 0
2 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
Sara made enough raspberry jam to fill 3
NeTakaya

Answer:

5/8 Jar

Step-by-step explanation:

I took the test...

3 0
3 years ago
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