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White raven [17]
3 years ago
10

Find the midpoint between ( - 1, 2) and (2, -3)​

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

(1/2, 0)

Step-by-step explanation:

Midpt=(x/2 +x/2) ; (y/2 +y/2)

(-1/2 + 2/2) ; (3/2 + -3/2)

(1/2 ; 0)

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Solve for q. √3q + 2 = √5
34kurt

Answer:

q = 0.0186

Step-by-step explanation:

To solve for q, we initially place everything with the term q to one side of the equality, and everything without the term q to the other side of the equality.

So

\sqrt{3q} + 2 = \sqrt{5}

\sqrt{3q} = \sqrt{5} - 2

We find the square of both sides of the equation. So

(\sqrt{3q})^{2} = (\sqrt{5} - 2)^{2}

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vaieri [72.5K]

Answer:

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Step-by-step explanation:

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The applicable rules of exponents are ...

  (a/b)^c = (a^c)/(b^c)

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7 0
3 years ago
Solve 14x + 1 = 36.<br> Round to the nearest ten-thousandth.
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Answer:

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Step-by-step explanation:

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x = log(36)/log(14) - 1 . . . . Subtract both sides by 1.

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Note that the second problem is similar  to the first.

2. 12^(y - 2) = 20

(y - 2)log(12) = log(20)

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nlexa [21]
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Answer:

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