if the diameter is 10, its radius is half that, or 5.
![\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3}\implies V=\cfrac{500\pi }{3} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill V\approx 523.599~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D5%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B4%5Cpi%20%285%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B500%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20V%5Capprox%20523.599~%5Chfill)
Answer:
Step-by-step explanation:
Given that,
y = x + 6 equation 1
3x - 3y = -18. Equation 2
Substitute equation 1 into equation 2
3x-3(x+6) = -18
3x - 3x - 18 = -18
-18 = -18
Therefore, it has no solution. Check attachment for echelon matrix solution
B. y = -2x + 5 equation 1
2x + y = -7. Equation 2
Substitute equation 1 into 2
2x -2x + 5 = -7
5 = -7
Since the equation is not balance, then, it has infinite numbers of solution.
C. y = -4x + 11. Equation 1
6x + y = 11. Equation 2
Substitute equation 1 into 2
6x - 4x + 11 = 11
2x = 11 - 11
2x = 0
x = 0
Also, y = -4x + 11
y = 0 + 11 = 11
Then, this has a unique solution I.e. one solution.
Answer: 11.67
Proportion:
12 = x
— —
6 5
Cross multiply.
70= 6x
Divide each side by 6
X= 11.67
Answer: true
Step-by-step explanation: