Answer:
Step-by-step explanation:
<u>Find the m∠B:</u>
- m∠B = (360° - 310°) + 50° = 100°
a)
<u>Find AC using law of cosines:</u>
- AC = √(8² + 13² - 28*13*cos 100°) = 16.4 km (rounded)
b)
<u>Find m∠A using law of sines:</u>
- 16.4/ sin 100 = 13 / sin A
- m∠A = arcsin (13 sin 100 deg / 16.4) = 51° (rounded)
<u>The bearing of C from A:</u>
c)
<u>Let the required distance is x:</u>
- x/ BC = sin 50°
- x = BC sin 50°
- x = 13 sin 50°
- x ≈ 10 km (rounded)
Answer: hahahaha you really thought i was going to give u the answer learn from your teacher stop cheating.
Given equations are;<span>
2a + 3b = -1 ..................equation 1
3a + 5b = -2 ....................equation 2</span>
Now multiply equation 1 with (-3)
The equation will be;
-6a -9b = 3 …………………..equation 3
Now multiply equation 2 with (2)
The equation will be;
6a + 10b = -4 ……………..equation 4
Now add equation 3 and equation 4
-6a – 9b = 3
<span>6a + 10b = -4</span>
<span>------------------------------</span>
0a + b = -1
b = -1
Now put the value of b in equation 1
2a + 3(-1) = -1
2a -3 = -1
2a = -1+3
2a = 2
a=1
Thus the solution is (a,b) = (1,-1)
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Answer:
A) Contraction
Step-by-step explanation: