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AnnZ [28]
3 years ago
9

Find the square root of 312.5​

Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

17.67766953

=17.7 (to 3 s.f.)

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For the function, find all critical numbers and then use the second-derivative test to determine whether the function has a rela
Serhud [2]

Answer:

relative maximum: x = 1

relative minimum: x = 7

Step-by-step explanation:

Critical points:

Values of x for which f'(x) = 0.

Second derivative test:

For a critical point, if f''(x) > 0, the critical point is a relative minimum.

Otherwise, if f''(x) < 0, the critical point is a relative maximum.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

f(x) = x^{3} - 12x^{2} + 21x - 8

Finding the critical points:

f'(x) = 3x^{2} - 24x + 21

3x^{2} - 24x + 21 = 0

Simplifying by 3

x^{2} - 8x + 7 = 0

So a = 1, b = -8, c = 7

\bigtriangleup = (-8)^{2} - 4*1*7 = 36

x_{1} = \frac{-(-8) + \sqrt{36}}{2} = 7

x_{2} = \frac{-(-8) - \sqrt{36}}{2} = 1

Second derivative test:

The critical points are x = 1 and x = 7.

The second derivative is:

f''(x) = 6x - 24

f''(1) = 6*1 - 24 = -18

Since f''(1) < 0, at x = 1 there is a relative maximum.

f''(7) = 6*7 - 24 = 18

Since f''(x) > 0, at x = 7 there is a relative minumum.

8 0
3 years ago
A shop keeper bought 26 apples from a fruit vendor for $37.70. How much did each apple cost?
Semenov [28]
You have to divide 37.70. By 26
3 0
4 years ago
Read 2 more answers
6 = 2p + 8 please i will give brainliest
Rzqust [24]
P = -1

Explanation: Subtract 8 on both sides and then divide by 2 on both sides

Please give brainliest!! :)
4 0
2 years ago
Read 2 more answers
Your parent’s mortgage is $231,450 at a 4.65% APR. If they pay $2,236 toward the mortgage each month, how much of the second mon
dsp73

Answer:

The principle applied for second month payment is $1,339.13

B is correct

Step-by-step explanation:

Mortgage value = $231,450

APR = 4.65%

Monthly Payment = $2,236

First month interest of $231,450 of APR 4.65%

Interest =231450\times \dfrac{0.0465}{12}

Interest of first month = $896.87

Monthly payment = $2,236

Second month's payment is applied toward the second month's principal

= Monthly Payment - First month Interest

= 2236 - 896.87

= 1339.13

Hence, The principle applied for second month payment is $1,339.13

5 0
4 years ago
you are draining a fish pond. The amount Y in liters of water remaining after X hours is y equals -60x + 480 a graph the equatio
Sergeu [11.5K]

Answer:

The graph in the attached figure

see the explanation

Step-by-step explanation:

Let

x----> the time in hours

y ----> liters of water remaining in the fish pond

we have

y=-60x+480

This is the equation of a line in slope intercept form

y=mx+b

where

m is the slope or unit rate

b is the y-intercept or initial value

In this problem we have

The slope or unit rate is equal to

m=-60\ \frac{liters}{hour} ----> is negative because is a decreasing function

The y-intercept or initial value is

b=480\ liters

The graph in the attached figure

Remember that

The y-intercept is the value of y when the value of x is equal to zero

The y-intercept is the point (0,480)

That means----> The initial amount of liters of water in the fish pond was 480 liters before drainage began (for x=0 hours).

The x-intercept is the value of x when the value of y is equal to zero

The x-intercept is the point (8,0)

That means----> The time required to empty the fish pond is 8 hours (for y=0 liters)

7 0
3 years ago
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