The rhombus always has perpendicular diagonals.
If the 4th lies opposite the 11th, then you know the 3rd lies opposite the 10th, the 2nd opposite the 9th, and the 1st opposite the 8th; meanwhile, in the reverse direction you'd find that the 5th lies opposite the 12th, the 6th opposite the 13th, and the 7th opposite the 14th. Move up one more bead and you're back at the 1st, which you already know lies opposite the 8th. Therefore there are 14 total beads.
Answer:
B y = 3x^2 + 12x + 19
Step-by-step explanation:
y = 3(x + 2)^2 + 7
To expand the square of the binomial,
either recall that (a + b)^2 = a^2 + 2ab + b^2, or use FOIL.
y = 3(x^2 + 4x + 4) + 7
y = 3x^2 + 12x + 12 + 7
y = 3x^2 + 12x + 19
Answer: B y = 3x^2 + 12x + 19
First you can take out a 3. And an x and a y. Thus, 3xy(3x+4y) is the answer.
