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mariarad [96]
2 years ago
9

When 12 is added to 4 times a number, the result is 44. What is the number?​

Mathematics
2 answers:
Anuta_ua [19.1K]2 years ago
7 0
Answer: 8

4x+12=44
subtract 12
4x=32
divide by 4
x=8

check work:
4(8)+12=44

Serggg [28]2 years ago
7 0

Answer:

4x+ 12 = 44

4x = 32

x = 8

Step-by-step explanation:

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GUYS I NEED HELP PLSSSSSS! Ive been working on this ALL day!
Vika [28.1K]

First, let's write what we know.

We can represent the number of students in the play from each class as L, G, and C. We know that L = 7, and if Gardener has 4 more students than Cho, then G = C + 4.

Then, taking the third line, we can write an inequality:

C < L < G

C < 7 < C + 4

C - 4 < 3 < C

3 < C < 7

If C is greater than 3 and less than 7 and is an integer, than means C is 4, 5, or 6.

Then, we need to find how many students are in the play.

C + L + G

C + 7 + C + 4

2C + 11

So we have our expression for the number of students in the play. Then, we need to find the total number of students. We know that 2C + 11 will be 30% of the total, so if T is the total, we can find T.

0.3T = 2C + 11

(Divide by 3/10 or multiply by 10/3 on both sides)

T = 20/3 C + 110/3

We know from before that C is 4, 5 or 6. We can plug these into our equation here to find which one produces a whole number.

T = 20/3 * 4 + 110/3

T = 190/3

T = 20/3 * 5 + 110/3

T = 210/3

T = 70

T = 20/3 * 6 + 110/3

T = 230/3

We can see here that only when C is 5 will the total be a whole number. That means Mrs. Cho has 5 students in the play. If Mrs. Gardner has 4 more than that, she has 9 students in the play in her class.  We now need to figure out the number of student in her class.

The total students are Cho's, Logan's, and Gardner's classes added together. We know that Logan's class is 23 students, so if we subtract that from the total, we can see that Cho's and Gardner's class have 47 students. If Mrs. Cho has 24 students in her class, we can subtract that from the 47, so we know that Mrs. Gardner has 23 students in her class.

4 0
3 years ago
Annette plans to visit an amusement park where she must pay for admission and
natulia [17]

Answer:

...

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours
Arada [10]

Answer:

The number of bacteria at initial = 187

Step-by-step explanation:

Given that the population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t.

\frac{dN}{dt} = k N

\frac{dN}{N}  = k dt

Integrating both side we get

㏑ N = k t + C ------- (1)

Now given that after 3 hours it is observed that 500 bacteria are present and after 10 hours 5000 bacteria are present.

⇒ ㏑ 500 = 3 k + C -------- (2)

⇒ ㏑ 5000 = 10 k + C ------ (3)

⇒ ㏑ 5000 -  ㏑ 500 = 7 k

⇒ ㏑\frac{5000}{500} = 7 k

⇒  ㏑ 10 = 7 k

⇒ k = 0.329

Put this value of k in equation (2),

⇒ ㏑ 500 = 3 × 0.329 + C

⇒ C = 5.23

Put this value of C in equation 1 we get,

⇒ ㏑ N = k t + 5.23

Initially when t = 0 , then

⇒ ㏑ N = 5.23

⇒ N =  187

Thus the number of bacteria at initial = 187

8 0
3 years ago
I need help with no.7
ziro4ka [17]

Answer:

  (a) 315°

  (b) 3°

  (c) 238°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

<h3>(a)</h3>

The bearing of P from R is 180° different from the bearing of R from P it will be ...

  135° +180° = 315° . . . . bearing of P from R

__

<h3>(b)</h3>

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

  315° +48° = 363°, or 3° . . . . bearing of Q from R

__

<h3>(c)</h3>

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

  180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

  135° -77° = 58°

As above, the reverse bearing from Q to P is ...

  58° +180° = 238° . . . . bearing of P from Q

8 0
2 years ago
Simplify (7/9a+9/7b)^2-ab
lianna [129]
Ab+49/81a^2+81/49b^2
7 0
3 years ago
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