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serg [7]
3 years ago
7

Can someone help me with this subtraction integers worksheet plzzzzzz.

Mathematics
2 answers:
Andre45 [30]3 years ago
7 0

Answer:

sorry i can solve questions of level seven maybe I can help you with something else

Step-by-step explanation:

thank you!!!

vredina [299]3 years ago
7 0
Is this how your supposed to do it? I don’t remember doing this in school but if this is how you’re supposed to do them then ill do the rest of them they’re pretty easy (unless thats not how its done)

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A circle is placed in a square with a side length of 18 mm, as shown below. Find the area of the shaded region.
finlep [7]
Answer: the shaded region = 69.66mm^2

Explanation:
Assume shaded region is X
Then :
X + Area of circle = area of square
X = area of square - area of circle

Find area of square:
Side length = 18mm
Area = 18 x 18 = 324

Find area of circle:
Side length of a square = the diameter of the circle = 18mm
And r(radius) = d/2 = 18/2 = 9
Area = pi x 9^2 = 254.34

Now find X
X = 324 - 254.34 = 69.66
3 0
3 years ago
Change 53/5 from an improper fraction to a mixed number.
Ilya [14]

Answer:

10.6

Step-by-step explanation:

53/5

7 0
3 years ago
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Convert -√3-i to polar form
djyliett [7]

Answer:

r

sin

θ

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Find the volume of the given prism. Round to the nearest tenth if necessary.
Alisiya [41]
Hello!

To find the volume of a rectangular prism you do hwl

h is height
w is width
l is length

4.2 * 5.3 * 12.1 = 269.346

The answer is 269.3 cubic centimeters

Hope this helps!
6 0
3 years ago
I REALLY NEED HELP PLEASE!!  
disa [49]


part A)

\bf \begin{array}{ccllll}
hours(x)&velocity(y)\\
-----&-----\\
1&6\\
3&2
\end{array}\\\\
-------------------------------\\\\


\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 1}}\quad ,&{{ 6}})\quad 
%   (c,d)
&({{ 3}}\quad ,&{{ 2}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-6}{3-1}\implies \cfrac{-4}{2}\implies -2

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-6=-2(x-1)\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-6=-2x+2\implies y=-2x+2+6\implies \boxed{y=-2x+8}

part B)

well, we know y = -2x+8.... so.. what's the runner's velocity after 5hours? well, x = 5, thus y = -2(5) +8 ---> y = -2

to graph it, well, is a LINEar equation, meaning the graph is a LINE, and to graph a line, all you need is two points, and by now, you have more than two.. so graph it away.
7 0
3 years ago
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