Question

PLEASE HELP !!!!!!!!!!

Answer 1

Answer:

IT IS A ISOCLES TRIANGLE

PLS MARK ME AS BRAINLIEST

GOD WILL BLESS YOU:)

Given:-

Given:-AB = AC

Given:-AB = ACAlso , BD and CE are two medians

Given:-AB = ACAlso , BD and CE are two mediansHence , 

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB and

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CE

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2AC

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD 

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]BC = CB [ Common ]

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]BC = CB [ Common ]Hence ,

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]BC = CB [ Common ]Hence ,Δ BEC ≅ ΔCDB [ SAS ]

Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]BC = CB [ Common ]Hence ,Δ BEC ≅ ΔCDB [ SAS ]BD = CE (by CPCT)