Answer:
IT IS A ISOCLES TRIANGLE
PLS MARK ME AS BRAINLIEST
GOD WILL BLESS YOU:)
Given:-
Given:-AB = AC
Given:-AB = ACAlso , BD and CE are two medians
Given:-AB = ACAlso , BD and CE are two mediansHence ,
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB and
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CE
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2AC
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]BC = CB [ Common ]
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]BC = CB [ Common ]Hence ,
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]BC = CB [ Common ]Hence ,Δ BEC ≅ ΔCDB [ SAS ]
Given:-AB = ACAlso , BD and CE are two mediansHence , E is the midpoint of AB andD is the midpoint of CEHence ,1/2 AB = 1/2ACBE = CD In Δ BEC and ΔCDB ,BE = CD [ Given ]∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]BC = CB [ Common ]Hence ,Δ BEC ≅ ΔCDB [ SAS ]BD = CE (by CPCT)
