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vagabundo [1.1K]
3 years ago
6

 A car whose initial speed is 30 m/s slows uniformly to 10 m/s in 5 seconds. Determine the acceleration of the car. Sketch a gra

ph to support your answer. CHALLENGE: Determine the distance it travels in the 3 seconds.
This one is a little harder because you have to make a graph :(
Physics
1 answer:
Anton [14]3 years ago
5 0
  • Initial velocity=u=30m/s
  • Final velocity=v=10m/s
  • Time=5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{10-30}{5}

\\ \sf\longmapsto Acceleration=\dfrac{-20}{5}

\\ \sf\longmapsto Acceleration=-4m/s^2

Now

For the second question

  • Time=3s

Using 2nd equation of motion

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto s=30(3)+\dfrac{1}{2}(-4)(3)^2

\\ \sf\longmapsto s=90-2(9)

\\ \sf\longmapsto s=90-18

\\ \sf\longmapsto s=72m

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If you know how much radioactive material the organism had to begin with, explain how you could use half-life to determine its a
TiliK225 [7]

Answer: We can calculate it with the radioactive half life equation

Explanation:

If we already know the initial amount of radioactive material and its half life, we can leave that material for a specific known time and then measure how much of the material is left (since it follows the radioactive deacay) and use the results in the following formula:

A=A_{o}.2^{\frac{-t}{h}}  

Where:

A is the final amount of the material

A_{o} is the initial amount of the material

t is the time elapsed

h is the half life of the radioactive compound

5 0
3 years ago
The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m^2 . The wave is incident
Alchen [17]

Answer:

47 mW

Explanation:

The average value of the Poynting vector, S = 0.939 W/m² = Intensity of wave, I

S = I S

Also, I = P/A where P = Et, P = power of electromagnetic wave, E = energy of electromagnetic wave in time t and t = time = 1 min = 60 s and A = area = lb since the electromagnetic waves falls on area equal to that of a rectangle.

So, S = Et/A

E = SA/t

= Slb/t

= 0.939 W/m² × 1.5 m × 2.0 m/60 s

= 2.817 W/60 s

= 0.047 W

= 47 mW

So, 47 mW of electromagnetic energy falls on the area in 1.0 minute.

4 0
3 years ago
A vector of magnitude 20 is added to a vector of magnitude 25. The magnitude of this sum. might be:. A. zero. B. 3. C. 12. D. 47
kiruha [24]
The correct answer among the choices provided is option C. The magnitude of the sum of 20 and 25 might be 12. Inequality triangle equation is used to determine if 12 is right.
<span>12+20 > 25 (correct)
12+25 > 20 (correct)
20+25 > 12 (correct)</span>
6 0
3 years ago
To review the solution to a similar problem, consult Interactive Solution 1.43. The magnitude of a force vector is 87.4 newtons
trasher [3.6K]

Answer:

(a) 34.4°

(b) 49.4 N

Explanation:

(a) From the diagram,

Amgle between the x axis can be calculated as,

cosΘ = adjacent/hypoteneous

cosΘ = 72.1/87.4

cosΘ = 0.8249

Θ = cos⁻¹(0.8249)

Θ = 34.4°.

Hence the angle between the x axis is 34.4°

(b) To find the component along the y axis we make use of pythagoras theorem.

a² = b²+c²................... Equation 1

Where a = 87.4 N, b = 72.1 N, c = y.

Substitute  these values into equation 1

87.4² = 72.1² + y²

y² = 87.4²-72.1²

y² = 2440.35

y = √(2440.35)

y = 49.4 N

7 0
3 years ago
As in Problem A above, a block of mass M starts from rest and is pushed up a frictionless ramp inclined at an angle θ above the
Tasya [4]

Answer:

A(i)

The solution to this question is shown on the second uploaded image

A(ii)

The final speed is v = \sqrt{2L (\frac{F}{M} - gsin\theta )}

B

The block speed after a distance L  is  v= \sqrt{2L (\frac{F}{M} -gsin \theta )}

Explanation:

From the question  

The net force i the x-direction is mathematically represented as

               F_{net} = Ma

From the the diagram in the second uploaded image we see that

             F_{net} = F - Mgsin \theta

Therefore

              F- Mgsin\theta = Ma

Making a the subject

              a = \frac{F}{M} - gsin\theta

Applying the law of motion

                v^2 =u^2 + 2as

where  u = 0 m/s and s =L

       v^2 = 0 + 2(\frac{F}{M} - gsin \theta )L

=>   v = \sqrt{2L (\frac{F}{M} - gsin\theta )}

According to Energy conservation law and work theorem

           Workdone by F + Workdone by gravity = change in kinetic energy

Mathematically this is given as

                F * L - (mgsin \theta)L = \frac{1}{2} M (v^2-u^2)

   Since u = 0 m/s

                    L (\frac{F}{M} - gsin \theta ) = \frac{1}{2} v^2

                  v= \sqrt{2L (\frac{F}{M} -gsin \theta )}

5 0
3 years ago
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