Let's start by differentiating the terms distance and displacement. They both refer to the length of paths. Distance only accounts for the total length regardless of the path taken. Displacement measures the linear path from the starting point to the end point. So, it does not necessarily follow the actual path. However, for this problem, assuming that the path is just in one direction, displacement and distance would just be equal. The equation would be:
Distance = Displacement = v₀t + 0.5at² = 0(10 s) + 0.5(+1.2 m/s²)(10 s)²
Distance = Displacement = 60 meters
Its b i belive
because it the only thing i saw on the list that conduts
Answer:
Answer:B
Explanation:
Because it all stayed consistant
To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:
Where,
= Mass of each object
= Initial Velocity of Each object
= Final Velocity
Our values are given as
Replacing we have that
Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s
PITCH
please mark brainliest!!!
