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Lesechka [4]
3 years ago
15

Which of the following statements is

Physics
2 answers:
ladessa [460]3 years ago
8 0
I’m pretty sure it’s B

B: If an object has mass, it has gravity.
myrzilka [38]3 years ago
3 0
The answer is B........
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You need to consider the following:
Me (mass of Earth) = 5.98 x 10^24 kg 
<span>Ms (mass of Sun) = 1.99 x 10^30 kg </span>
<span>G = 6.67 x 10^-11 N </span>
<span>
Formula:
 F = G * M1M2/r^2 
</span><span>The ratio FT/F = 4.02x10^-4 / 14.8
 = 2.72x10^-5 
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Since,
1/2.72x10^-5 = 36800
The fraction ratio is  1/36800
</span>= <span>9.56x10^17 N</span>
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A ball rolls off a table and it traveling with a horizontal velocity of 2 m/s and 1 point
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Answer:

The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.

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If a sprinter has an average acceleration of 9.5 m/s2, how long does it take for the person to go from rest to 10 m/s
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A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of
kirill [66]

Answer:A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of the ice block melted as a result of the work done by friction? (Latent Heat of water is 3.3*10^5J/kg)

Explanation:

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3 years ago
Indigenous people sometimes cooked in watertight baskets by placing enough hot rocks into the water to bring it to a boil. What
yaroslaw [1]

Answer:

The rock has a mass of 4.02 kg

Explanation:

<u>Step 1: </u>Data given

Mass of the rock = TO BE DETERMINED

Temperature of the rock = 500 °C

Mass of the water  =4.24 kg

⇒ loses 0.044kg as vapor

Initial temperature of the water = 29°C

Final temperature = 100°C

Specific heat of rock = 0.20 kcal/kg °C

Specific heat of water = 1kcal/kg°C

Latent heat of vaporization = 539 kcal/kg

<u>Step 2:</u> formules

Qlost,rock + Qgained,water = 0

Qtotal,water = Qwater +Qvapor

<u>Step 3: </u>Calculate Qvapor

Qvapor = mass of vapor * Latent heat of vapor

Qvapor = 0.044kg * 539 kcal/kg = 23.716 kcal

<u>Step 4: </u>Calculate Qwater

Qwater = mass of water * specific heat * Δtemperature

Qwater = 4.196 kg * 1kcal/kg°C *( 100-29)

Qwater = 297.916 kcal

<u>Step 5:</u> Calculate Qwater,total

Qwater,total = Qwater + Qvapor

Qwater,total = 23.716 kcal + 297.916 = 321.632 kcal

<u>Step 6</u>: Calculate Qrock

Qrock = mass of rock * specific heat rock * Δtemperature

Qrock = mass of rock * 0.20 kcal/kg°C * (100-500)

Qrock = mass of rock * -80 kcal/kg

<u>Step 7:</u> Calculate mass of rock

Qlost,rock + Qgained,water = 0

Qlost,rock = -Qgained,water

mass of rock * -80 kcal/kg = -321.632 kcal

mass of rock = 4.02 kg

The rock has a mass of 4.02 kg

7 0
3 years ago
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