Answer:
True
Explanation:
The tensile stress, σ, on a solid cylindrical wire is given by the following relationship;

Where;
= The tensile force
= The original cross sectional area of the cylindrical wire = π·R²
R = The radius of the wire
Therefore;
= σ ×
= σ × π × R²
Therefore, the tensile force is directly proportional to the square of the radius of the cylindrical wire, and as the radius of the wire increases, which is by increasing the thickness of the wire, the tensile force is largely increased
The correct option is; True.
Answer:
potential energy = mgh
= 400÷1000 × 10× 4÷100
= 0.4 × 10 × 0.04
=4/10 ×10×4/100
= 4/10 × 4/10
=16/100
= 0.16 joules
m1 (400) stretches 4cm
m1 (100g) stretches 1cm
so, m2(800g) stretches 8 cm
potential energy of m2 = mgh
= 800/1000 ×10×8/100
= 0.8 × 0.8
=8/10 ×8/10
= 64/100
=0.64 joules
Ratio of s1 to s2
16/100 ÷ 64/100
= 1:4 ( answer)
As per Newton's II law we know that

here
F = applied unbalanced force
m = mass of object
a = acceleration of object
now it is given that force F = 50 N North applied on block on earth due to which block will accelerate by 4 m/s^2
so here from above equation


Now we took another situation where block is placed on surface of moon and again force F = 25 N is applied on the block
So we will again use Newton's II law




so block will accelerate on moon by acceleration 2 m/s^2
The force of a charge in an electric field is:

In this case we know the electric field is:

and that the charge is that of the electron, then we have:

Therefore, the magnitude of the force is

and in points down.
The weight of the electron is:

Making the quotient between the force we have:

Therefore, the electric force is approximately 1e9 times the weight.
Answer:
Gravitational potential energy
Explanation:
The gravitational potential energy is the energy that an object has because of its positive with respect to a certain reference level (generally assumed to be the ground level).
The magnitude of the gravitational potential energy is given by

where
m is the mass of the object
g is the strenght of the gravitational field
h is the height of the object with respect to the reference level
From the formula, we see that the higher the object is, the larger its gravitational potential energy is.