Equation 1) 3x + 2y - 5z = 3
Equation 2) 4x - 2y - 3z = -10
Equation 3) 5x - 2y - 2z = -11
Add equation 1 with equation 2.
Equation 4) 7x - 8z = 7
Then subtract equation 3 from equation 2.
Equation 5) -x -z = 1
Multiply all of equation 5 with 7.
5) -7x - 7z = 7
4) 7x - 8z = 7
Add equations together.
z = 14
Plug in 14 for z in equation 4.
7x - 8z = 7
7x - 8(14) = 7
7x - 112 = 7
7x = 119
x = 17
Plug in 17 for x in equation 1, and 14 for z.
1) 3x + 2y - 5z = 3
3(17) + 2y - 5(14) = 3
51 + 2y - 70 = 3
2y - 19 = 3
2y = 22
y = 11
So, x = 17, y = 11, and z = 14
~Hope I helped!~
A. terms is the best way to describe them
The values of the letters in coordinates (a, b) and (c,d) are;
<u><em>a = -4</em></u>
<u><em>b = -6</em></u>
<u><em>c = 2</em></u>
<u><em>d = 6</em></u>
<u><em /></u>
We are given two equations;
-6x + 3y = 6 ---(eq 1)
x² + y = 10 ---(eq 2)
- We are told that they intersect at coordinates; (a, b) and (c, d).
Let us make y the subject in eq 2 to get;
y = 10 - x² --(eq 3)
- Let us put 10 - x² into eq 1 to get;
-6x + 3(10 - x²) = 6
expanding further gives;
-6x + 30 - 3x² = 6
rearranging gives;
3x² + 6x - 24 = 0
Using online quadratic equation <em>solver</em>, we have;
x = -4 and x = 2
Putting x = -4 into eq 3 gives;
y = 10 - (-4)²
y = 10 - 16
y = -6
Putting x = 2 into eq 3 gives;
y = 10 - (2)²
y = 10 - 4
y = 6
- Thus, the coordinates are; (-4, -6) and (2, 6)
Comparing with (a, b) and (c,d), we have;
a = -4
b = -6
c = 2
d = 6
Read more at; brainly.com/question/15165519
Variable equals 12
Equation equals 16m+12b=112
Solution you just divide 112 by the product of 16+12
